Question

Your electric drill rotates initially at 5.35 rad/s. You slide the speed control and cause the drill to undergo constant angular acceleration of 0.331 rad/s2 for 4.81 s. What is the drill's angular displacement during that time interval?

Answer 1

Answer:

The  angular displacement  is  $\theta = 29.6 \ rad$

Explanation:

From the question we are told that

     The initial angular speed is  $w = 5.35 \ rad/s$

      The angular acceleration is  $\alpha = 0.331 rad /s^2$

      The time take is  $t = 4.81 \ s$

     

Generally the angular displacement is mathematically represented as

          $\theta = w * t + \frac{1}{2} \alpha * t^2$

substituting values

         $\theta = 5.35 * 4.81 + \frac{1}{2} * 0.331 * (4.81)^2$

         $\theta = 29.6 \ rad$