We got the following:
m = 78kg
h = 6m
g = 9.8 m/
≈ 10 m/
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A = ?
As we know A = Ep = mgh -> potential energy
so the answer would be A = 78 * 6 * 10 = 4680 Joule
Answer:
V=34.2 m/s
Explanation:
Given that
Height , h= 54 m
Horizontal distance , x = 35 m
Given that , the ball is thrown horizontally , therefore the initial vertical velocity will be zero.
In vertical direction :
We know that
Now by putting the values in the above equation we got
Assume 
Thus
We also know that
In horizontal direction :
Thus the resultant velocity
V=34.2 m/s
Therefore the velocity will be 34.2 m/s.
Ahhh, there aren’t option to work with :v
Try writing them down here thnx
Answer:
132 N
Explanation:
Given that a 1.1 kg hammer strikes a nail. Before the impact, the hammer is moving at 4.5 m/s; after the impact it is moving at 1.5 m/s in the opposite direction. If the hammer is in contact with the nail for 0.025 s, what is the magnitude of the average force exerted by the hammer on the nail
From Newton 2nd law of motion,
Change in momentum = impulse.
Change in momentum = m( V - U )
Substitute all the parameters into the formula
Change in momentum = 1.1 ( 4.5 - 1.5 )
Change in momentum = 1.1 × 3
Change in momentum = 3.3 kgm/s
Impulse = Ft
That is,
Ft = 3.3
Substitute time t into the formula above
F × 0.025 = 3.3
F = 3.3 / 0.025
F = 132 N
Therefore, the magnitude of the average force exerted by the hammer on the nail is 132 N.
Answer:
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Explanation:
what they said is correct
