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kotegsom [21]
3 years ago
6

Write the symbol for every chemical element that has an atomic number less than 13 and atomic mass greater than 19.3 u

Chemistry
1 answer:
emmainna [20.7K]3 years ago
3 0

Answer:

The symbol of each element is, Ne, Na, Mg, and Al.

Explanation:

Below is the list of elements that has an atomic mass of less than 19.3 u.

The atomic mass of Neon is 20.1797 u and the atomic number is 10.

The atomic mass of Sodium is 22.989769 u and the atomic number is 11.

The atomic mass of Magnesium is 24.305 u and the atomic number is 12.

The atomic mass of Aluminium is 26.981539 u and the atomic number is 13.

Here, the symbol of each element is, Ne, Na, Mg, and Al.

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Energy levels of the Atom O
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Answer:

Oxygen has 2 energy levels

Explanation:

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2 years ago
A chemist fills a reaction vessel with mercurous chloride solid, mercury (I) aqueous solution, and chloride aqueous solution at
makvit [3.9K]

Answer:

ΔG° = -533.64 kJ

Explanation:

Let's consider the following reaction.

Hg₂Cl₂(s) ⇄ Hg₂²⁺(aq) + 2 Cl⁻(aq)

The standard Gibbs free energy (ΔG°) can be calculated using the following expression:

ΔG° = ∑np × ΔG°f(products) - ∑nr × ΔG°f(reactants)

where,

ni are the moles of reactants and products

ΔG°f(i) are the standard Gibbs free energies of formation of reactants and products

ΔG° = 1 mol × ΔG°f(Hg₂²⁺) + 2 mol × ΔG°f(Cl⁻) - 1 mol × ΔG°f(Hg₂Cl₂)

ΔG° = 1 mol × 148.85 kJ/mol + 2 mol × (-182.43 kJ/mol) - 1 mol × (-317.63 kJ/mol)

ΔG° = -533.64 kJ

3 0
3 years ago
Tin reacts with Fluorine to form two different compounds, A and B. Compounds A contains 77.0 g tin for each 24.6 g of fluorine.
Ratling [72]
A contains 38.5 g of tin for each 12.3 g of fluorine: 
<span>mole ratio: </span>
<span>(38.5 g)/(118.71 g/mol):(12.3 g)/(18.998 g/mol) = 0.324:0.647 = 1:2 ⇒ SnF₂ </span>

<span>B contains 56.5 g of tin for each 36.2 g of fluorine: </span>
<span>mole ratio: </span>
<span>(56.5 g)/(118.71 g/mol):(36.2 g)/(18.998 g/mol) = 0.476:1.905 = 1:4 ⇒ SnF₄

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3 0
3 years ago
Read 2 more answers
Calculate the molar concentration of the polycyclic aromatic hydrocarbon (pah), anthracene (178.23 g/mol), that was found in a w
tester [92]

solution:

Calculate the molar concentration of the polycyclic aromatic hydrocarbon(PHA)(178.23g/mol),that was found in a well water sample at a concentration of 6.21ppb.Assume the density of the water is 1.00mg/mLppb corresponds to 1\mu g in 1L of sample \\the 6.21 ppb is 6.21\mu g in 1L of sample\\6.21\mu g PHA\times\frac{1mg PHA}{1000\mu g PHA}\times\frac{1g PHA}{1000\mu mg PHA}\times\frac{1mol. PHA}{178.23g PHA}\\3.48\times10^-8mol PHA\\and if we have 1L of solution\\m=\frac{moles}{v(L)}=\frac{3.48\times10^-8mol}{1L}\\3.348\times^10-8 M

3 0
3 years ago
Read 2 more answers
¿Cuál será la masa molar del agua?, si el hidrógeno tiene una masa atómica H=1.0 uma y el Oxigeno de 16 uma. * 1 punto
nataly862011 [7]

Answer:

18

Explanation:

Sabemos que la fórmula química del agua es H2O.

Usando la información que; H = 1, O = 16, podemos calcular la masa molar del agua de la siguiente manera

[2 (1) + 16] = 18

Por tanto, la masa molar del agua es 18

3 0
3 years ago
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