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OLga [1]
3 years ago
8

Type the correct answer in each box. In an atom, the first energy level can hold electrons. The second energy level can hold ele

ctrons. The third energy level can hold electrons.
Chemistry
2 answers:
Dimas [21]3 years ago
7 0
1st energy level can hold 2 electrons
2nd energy level can hold 8 electrons
3rd energy level can hold 8 or 18 electrons
ELEN [110]3 years ago
4 0

Answer:

In an atom, the first energy level can hold  <u><em>2</em></u> electrons. The second energy level can hold <em><u>8</u></em> electrons. The third energy level can hold  <u><em>18 </em></u>electrons.

Explanation:

There are 7 energy levels, numbered from 1 to 7, and in which electrons are distributed. Each level is divided into sub-levels. These sub-levels into which each level is divided can be up to 4 and these are called: s, p, d, f. In the sub-level s there can only be a maximum of 2 electrons, in p there can be a maximum of 6 electrons, in the sub-level d 10 electrons and finally in the sub-level f there can be a maximum of 14 electrons.

In level 1 there is only one sub-level, which will be the s. In level 2 there are 2 sub-levels, the s and the p. At level 3 there are 3 sub-levels s, p and d. And at level 4 there are 4 sub-levels, the s, the p, the d and the f.

As in level 1 there is only the sub-level s, and this sub-level can only contain 2 electrons at most, then <u><em>the first energy level can hold  2 electrons.</em></u>

As in level 2 there is the sub-level s and p, and these sub-levels can only contain 2 and 6 electrons at most respectively, by adding them you get that <u><em>the second energy level can hold 8 electrons.</em></u>

As in level 3 there is the sub-level s, p and d, and these sub-levels can only contain 2, 6 and 10 electrons at most respectively, by adding them you get that <u><em>the third energy level can hold 18 electrons.</em></u>

The maximum number of electrons in each level can also be calculated by means of the expression: 2*n², where n is the level to which the electrons belong. Then:

  • First Level: 2*1²= 2 electrons
  • Second Level: 2*2²= 8 electrons
  • Third Level: 2*3²= 18 electrons

You can see that you get the same amount of electrons, so either of the two ways of thinking is correct.

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A 25.00 ml solution of sulfuric acid H2SO4 is titrated to phenolphthalein end point with 27.00 ml of 1.700 M KOH
Nastasia [14]
<h3>Answer:</h3>

0.918 M

<h3>Explanation:</h3>

Assuming the question requires we calculate the Molarity of sulfuric acid:

We are given:

  • Volume of the acid, H₂SO₄ = 25.00 ml
  • Volume of the base, KOH = 27.00 mL
  • Molarity of the base, KOH is 1.70 M

We can calculate the molarity of the acid using the following steps;

<h3>Step 1: Write the chemical equation for the reaction.</h3>

The reaction is an example of a neutralization reaction where a base reacts with an acid to form salt and water.

Therefore, the balanced equation will be;

H₂SO₄(aq) + 2KOH(aq) → K₂SO₄(aq) + 2H₂O(l)

<h3>Step 2: Determine the moles of the base, KOH </h3>

When given molarity and the volume of a solution, the number of moles can be calculated by multiplying molarity with volume.

Number of moles = Molarity × Volume

                             = 1.700 M × 0.027 L

                              = 0.0459 moles

Thus, moles of KOH used is 0.0459 moles

<h3>Step 3: Determine the number of moles of the Acid, H₂SO₄</h3>

From the reaction, 1 mole of the acid reacts with 2 moles of KOH

Therefore, the mole ratio of H₂SO₄ to KOH is 1 : 2

Thus, moles of H₂SO₄ = Moles of KOH ÷ 2

                                     = 0.0459 moles ÷ 2

                                     = 0.02295 moles

<h3>Step 4: Calculate the molarity of the Acid </h3>

Molarity is the concentration of a solution in moles per liter

Molarity = Moles ÷ Volume

Molarity of the acid = 0.02295 moles ÷ 0.025 L

                                = 0.918 M

Thus, the molarity of the acid, H₂SO₄ is 0.918 M

5 0
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Determine the type of reaction for the following equation:<br> C2H6 + O2à H2O + CO2
valkas [14]

Answer:

The type of reaction for the following equation is combustion equation.

Explanation:

Combustion reaction is defined as the chemical reaction in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide gas and water molecule.

\text{hydrocarbon}+O_2\rightarrow CO_2+H_2O

The reaction given to us:

C_2H_6 + \frac{7}{2}O_2\rightarrow 3H_2O + 2CO_2

When 1 mole of ethane reacts with 7/2 moles of oxygen gas it gives 3 moles of water and 2 moles of carbon dioxide gas.

The type of reaction for the following equation is combustion equation.

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