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evablogger [386]
2 years ago
5

How many grams of mercury are present in a blood device that holds 6.9mL of mercury

Chemistry
1 answer:
lianna [129]2 years ago
7 0

Answer: 1

Explanation:it is common sense

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Find the numberof moles in 60 grams of SO3
ziro4ka [17]

The answer is in the photo

8 0
3 years ago
In the b-pleated sheet conformation A. there are hydrogen bonds perpendicular to the direction of the polypeptide chain.B. the p
inysia [295]

Answer:

D. all of these

Explanation:

Proteins are chains of amino acids (polypeptides) that adopt a specific conformation in space. To adopt this conformation, the amino acid chains fold locally and regularly, forming what is known as secondary structures. Mainly, there are two types of secondary structures: the α-helix and the β-pleated sheet.

In the α-helix, the polypeptide chain is spirally wound on itself. This structure is maintained thanks to hydrogen bonds between the carboxyl group of an amino acid and the amino group of the fourth amino acid that follows in the chain.

In the β-pleated sheet the polypeptide skeleton is almost extended in a zig zag shape and stability is achieved by the association of two or more peptide chains next to each other by hydrogen bonds between the amino and carboxyl groups of the peptide bond between adjacent chains. For this reason, hydrogen bonds are almost perpendicular to amino acid chains. In the image Bsheet this phenomenon can be observed.

Usually, the chains are drawn with an arrow to indicate the direction of the polypeptide chain from the amino group to the terminal carboxyl. Thus, adjacent chains of a beta sheet can be oriented in the same direction (parallel beta sheets), or in opposite directions (antiparallel beta sheets). The same folded beta sheet can have parallel and antiparallel chains. The image Bsheet 2 shows parallel and antiparallel chains.

4 0
3 years ago
Which of the following are properties of the oxides of non-
lina2011 [118]

Answer:

it is option A hope it helps

6 0
3 years ago
1- A sample of gas is in a 3.00 L contain at a pressure of 740.0 mmHg. What is the new pressure of the sample if the container's
inna [77]

Considering the Boyle's law, the new pressure of the sample is 1,776 mmHg.

<h3>What is Boyle's law</h3>

Boyle's law establishes the relationship between the pressure and the volume of a gas when the temperature is constant.

Boyle's law states that the volume occupied by a given mass of gas at constant temperature is inversely proportional to the pressure. This means that if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.

Boyle's law is expressed mathematically as:

P×V=k

Now it is possible to assume that you have a certain volume of gas V1 which is at a pressure P1 at the beginning of the experiment. If you vary the volume of gas to a new value V2, then the pressure will change to P2, and the following will be true:

P1×V1=P2×V2

<h3>New pressure</h3>

In this case, you know:

  • P1= 740 mmHg
  • V1= 3 L
  • P2= ?
  • V2= 1.25 L

Replacing in Boyle's law:

740 mmHg× 3 L=P2× 1.25 L

Solving:

P2= (740 mmHg× 3 L) ÷ 1.25 L

P2= 1,776 mmHg

Finally, the new pressure of the sample is 1,776 mmHg.

Learn more about Boyle's law:

brainly.com/question/4147359

#SPJ1

7 0
2 years ago
Read 2 more answers
Which of the following is not an oxidation-reduction reaction?
Art [367]

Answer: option C. NaCl + LiNO₃ ---> NaNO₃ + LiCl


Explanation:


1) An oxidation-reduction reaction is the oxidation of at least one element and the reduction of at least one element.


2) Oxidation is the increase of the oxidation number, due to the loss of electrons.


3) Reduction is the reduction of the oxidation number, due to the gain of electrons.


4) You can tell whenever a reaction is an oxidation-reduction by observing the oxidation numbers: if two elements changed its oxidation number (one increases and one reduces) it is an oxidation - reduction, else it is not.


5) Oxidation numbers:


i) NaCl


Na: 1+, Cl: 1-.


ii) LiNO₃


Li: 1+, N: 5+, O: 2-


iii) NaNO₃


Na: 1+, N: 5+, O: 2-


iv) LiCl


Li: 1+, Cl: 1-.


There you have that the oxidation numbers of the five elements (Na, N, O, Li, and Cl) remained unchanged.


None element was reduced and none element was oxidized, so you conclude that this is not an oxidation-reduction reaction.

6 0
4 years ago
Read 2 more answers
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