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Ivenika [448]
3 years ago
5

PLEASE HELP !! 15 POINTS Describe how you would separate a mixture of charcoal, iron filings, salt, and water. What phases of ma

tter are included in this mixture?
Chemistry
1 answer:
Blizzard [7]3 years ago
5 0
Ok look So you gotta use a magnet to attract the iron filings thats what I know But maybe I think you would use Evaporati
You might be interested in
14. How many grams of NaCl are contained in 0.350 kg of a
Lyrx [107]

Answer:

4.87g

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Mass of solution = 0.35kg

Molality = 0.238 m

Mass of NaCl =..?

Step 2:

Determination of the number of mole of NaCl in the solution.

Molality of a solution is simply defined as the mole of solute per unit kg of the solvent. It is given as:

Molality = mol of solute /mass of solvent (kg)

With the above formula, we calculate the mole of NaCl present in the solution as follow:

Molality = mol of solute /mass of solvent (kg)

0.238 = mol of NaCl /0.35

Cross multiply

mol of NaCl = 0.238 x 0.35

mol of NaCl = 0.0833 mol

Step 3:

Determination of the mass of NaCl in 0.0833 mol of NaCl.

This is illustrated below:

Number of mole NaCl = 0.0833 mol

Molar Mass of NaCl = 23 + 35.5 = 58.5g/mol

Mass of NaCl =..?

Mass = number of mole x molar Mass

Mass of NaCl = 0.0833 x 58.5

Mass of NaCl = 4.87g

Therefore, 4.87g of NaCl is contained in the solution.

5 0
4 years ago
report the elements half life. if we start with 100g of your element (platinum) how long will it take to have 6.26g?
pav-90 [236]

Answer:

did u get the answer yet

Explanation:

5 0
2 years ago
Rings are a characteristic of
Ymorist [56]

Answer:

physical

Explanation:

if it is asking to determine what it is a sign of or how to identify that characteristic it would be a physical.

3 0
3 years ago
An object with a pre-weighed mass of exactly (and correctly) 0.54 g is given to 2 students. One student obtains a weight of 0.59
Alina [70]

Answer:

Both student have same percent error.

Explanation:

Given data:

Actual mass of object = 0.54 g

Measured value by one student = 0.59 g

Measured value by second student = 0.49 g

Percent error = ?

Solution:

Formula

Percent error = (measured value - actual value / actual value) × 100

Percent error of first student:

percent error = (0.59 g - 0.54 / 0.54 ) ×100

percent error =  9.3 %

Percent error of second student:

Percent error = (0.49 g - 0.54 / 0.54 ) ×100

Percent error = - 9.3 %

Both student have same percent error. The only difference is that first student measure the greater value then actual value and second student measure the less value then actual, however difference was same and gives same percent error.

3 0
4 years ago
Looking for 14-16, hispanic, curly hair, genuinely a nice guy
wlad13 [49]

Answer:me being a tanned ginger

Explanation: i cant date u

8 0
4 years ago
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