Answer:
4.87g
Explanation:
Step 1:
Data obtained from the question. This includes the following:
Mass of solution = 0.35kg
Molality = 0.238 m
Mass of NaCl =..?
Step 2:
Determination of the number of mole of NaCl in the solution.
Molality of a solution is simply defined as the mole of solute per unit kg of the solvent. It is given as:
Molality = mol of solute /mass of solvent (kg)
With the above formula, we calculate the mole of NaCl present in the solution as follow:
Molality = mol of solute /mass of solvent (kg)
0.238 = mol of NaCl /0.35
Cross multiply
mol of NaCl = 0.238 x 0.35
mol of NaCl = 0.0833 mol
Step 3:
Determination of the mass of NaCl in 0.0833 mol of NaCl.
This is illustrated below:
Number of mole NaCl = 0.0833 mol
Molar Mass of NaCl = 23 + 35.5 = 58.5g/mol
Mass of NaCl =..?
Mass = number of mole x molar Mass
Mass of NaCl = 0.0833 x 58.5
Mass of NaCl = 4.87g
Therefore, 4.87g of NaCl is contained in the solution.
Answer:
physical
Explanation:
if it is asking to determine what it is a sign of or how to identify that characteristic it would be a physical.
Answer:
Both student have same percent error.
Explanation:
Given data:
Actual mass of object = 0.54 g
Measured value by one student = 0.59 g
Measured value by second student = 0.49 g
Percent error = ?
Solution:
Formula
Percent error = (measured value - actual value / actual value) × 100
Percent error of first student:
percent error = (0.59 g - 0.54 / 0.54 ) ×100
percent error = 9.3 %
Percent error of second student:
Percent error = (0.49 g - 0.54 / 0.54 ) ×100
Percent error = - 9.3 %
Both student have same percent error. The only difference is that first student measure the greater value then actual value and second student measure the less value then actual, however difference was same and gives same percent error.
Answer:me being a tanned ginger
Explanation: i cant date u
