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masha68 [24]
3 years ago
8

Please help!! Having trouble with this

Chemistry
1 answer:
Gnoma [55]3 years ago
7 0
For #4 first find the molar mass(M) of copper then use that and the mass (m) n=m/M to find moles(n) using moles and the volumes find the concentration using c=n/V
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The chemical equation provided shows iron rusting to form iron oxide. Use the drop-down menu to choose the coefficients that wil
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4Fe + 3O2 → 2Fe2O3 <or> The chemical formula for rust is Fe2O3. Rust is formed when iron reacts with oxygen in moist air. The following chemical equation represents the reaction: 4Fe + 3O2 → 2Fe2O3. Water is necessary for the oxidation reaction to occur and to facilitate transport of the electrons.

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A beaker of nitric acid is neutralized with dilute aqueous solution of calcium hydroxide.Write a net ionic equation for this rea
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Complete balanced equation: 2HNO₃  +  Ca(OH)₂  →  Ca(NO₃)₂  +  2H₂O

Ionized equation (with spectator ions): 
   2H⁺  +  2NO₃⁻  +  Ca²⁺  +  2OH⁻   →  Ca²⁺  +  2NO₃⁻  +  2H₂O

By eliminating the ions that are the same of both sides of the equation (spectator ions):
    
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If mixture didn't exist how would life be different​<br><br>PLEASEEE QUICKKKK
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Which of the following "spheres" is NOT involved in the water cycle?
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B is the correct answer.
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The following information is to be used for the next 2 questions. In order to analyze for Mg and Ca, a 24-hour urine sample was
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Answer:

Explanation:

From the given information:

The concentration of metal ions are:

[Ca^{2+}]= \dfrac{0.003474 \ M \times 20.49 \ mL}{10.0 \ mL}

[Ca^{2+}]=0.007118 \ M

[Mg^2+] = \dfrac{0.003474 \ M\times (26.23  - 20.49 )mL}{10.0 \ mL}

=0.001994 \ M

Mass of Ca²⁺ in 2.00 L urine sample is:

= 2.00 L \times 0.001994 \dfrac{mol}{L} \times \dfrac{40.08 \ g}{1 \ mol}

= 0.1598 g

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5 0
3 years ago
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