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2 years ago

Please help!! Having trouble with this

Chemistry

1 answer:

Gnoma [55]2 years ago

7 0

For #4 first find the molar mass(M) of copper then use that and the mass (m) n=m/M to find moles(n) using moles and the volumes find the concentration using c=n/V

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Explain how to convert a mass of compound A to a mass of compound D in words with no equations using the following reaction 2A +

leonid [27]

Answer:

Explanation:

The given reaction equation is:

2A + 4B → C + 3D

We know the mass of compound A in the reaction above. We are to find the mass of compound D.

We simply work from the known mass to calculate the mass of the unkown compound D

Using the mole concept, we can find the unknown mass.

Procedures

We first find the molar mass of the compound A from the atomic units of the constituent elements.
We then use the molar mass of A to calculate its number of moles using the expression below:

Number of moles of A = $\frac{mass of A}{molar mass of A}$

Using the known number of moles of A, we can work out the number of moles of D.

From the balanced equation of the reaction, it is shown that:

2 moles of compound A was used up to produced 3 moles of D

Then $\frac{3}{2}$ x number of moles of A would give the number of moles of D

Now that we know the number of moles of D, we can find its mass using the expression below:

Mass of D = number of moles of D x molar mass of D

8 0

2 years ago

17) A 0.20 M solution of HCl with a volume of 15.0 mL is exactly neutralized by the 0.10 M solution of NaOH with what volume? HI

galina1969 [7]

Answer: A 0.20 M solution of HCl with a volume of 15.0 mL is exactly neutralized by the 0.10 M solution of NaOH with 3 mL volume.

Explanation:

Given: $M_{1}$ = 0.20 M, $V_{1}$ = 15.0 mL

$M_{2}$ = 0.10 M, $V_{2}$ = ?

Formula used is as follows.

$M_{1}V_{1} = M_{2}V_{2}$

Substitute the values into above formula s follows.

$M_{1}V_{1} = M_{2}V_{2}\\0.20 M ]times 15.0 mL = 0.10 M ]times V_{2}\\V_{2} = 30 mL$

Thus, we can conclude that a 0.20 M solution of HCl with a volume of 15.0 mL is exactly neutralized by the 0.10 M solution of NaOH with 3 mL volume.

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