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Mrac [35]
3 years ago
12

Which contributes to the polarity of a water molecule? A. a linear shape along with strong covalent bonds B. deflection of hydro

gen atoms by lone pairs of electrons C. no difference in the electronegativity of oxygen and hydrogen D. hydrogen bond formation between water molecules
Chemistry
2 answers:
vodomira [7]3 years ago
4 0

Here we have to choose the correct statement behind the polarity of the water molecule.

The polarity of the water molecules is due to the B. deflection of the hydrogen atoms by the lone pair of electrons.

The bonding of the water (H₂O) molecule is shown in the figure. There remain two lone pair of electrons on the oxygen atom. The oxygen atom has 6 valence electrons among which 2 are involved to make the covalent bond with two hydrogen atom.

The lone pair if electrons exerted lone pair-bond pair repulsion and H₂O has a bent structure as shown in the figure. In this way the dipole moment generated by oxygen and hydrogen cannot be nullified and it has a permanent dipole moment which leads the molecule to be polar in nature.

The water molecule is not linear in nature it has bent structure.

There is a huge difference of electronegativity between the hydrogen (H) and oxygen (O) atom. The oxygen atom is highly electronegative whereas the hydrogen atom is electropositive in nature.

The hydrogen bond formation is due to the fact the molecule is polar in nature.

lozanna [386]3 years ago
4 0

Answer:

<h3>The answer is B</h3>

Explanation:

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Which type of combination is a mixture?
DochEvi [55]

Answer:

C.  physical

Explanation:

A mixture is a physical combination. Mixtures are combinations of compounds and molecules without any chemical reaction taking place.

Mixtures have the following properties:

  • They have an indefinite composition i.e they consist of two or more elements and or compounds in any proportion by mass
  • Their constituents retains their identities i. e physical property is retained.
  • Their constituents reacts differently to changed conditions.
  • They are easily separated into constituents by physical methods
8 0
3 years ago
In acidic aqueous solution, the purple complex ion Co(NH3)5Br2+ undergoes a slow reaction in which the bromide ion is replaced b
kirill115 [55]

Answer:

A) 0.065 M is its molarity after a reaction time of 19.0 hour.

B) In 52 hours [Co(NH_3)5Br]^{2+} will react 69% of its initial concentration.

Explanation:

Co(NH_3)_5(H_2O)_3+[Co(NH_3)5Br]^{2+}(Purple)(aq)+H_2O(l)\rightarrow [Co(NH_3)_5(H_2O)]^{3+}(Pinkish-orange)(aq)+Br^-(aq)

The reaction is first order in [Co(NH_3)5Br]^{2+}:

Initial concentration of [Co(NH_3)5Br]^{2+}= [A_o]=0.100 M

a) Final concentration of [Co(NH_3)5Br]^{2+} after 19.0 hours= [A]

t = 19.0 hour = 19.0 × 3600 seconds ( 1 hour = 3600 seconds)

Rate constant of the reaction = k = 6.3\times 10^{-6} s^{-1}

The integrated law of first order kinetic is given as:

[A]=[A_o]\times e^{-kt}

[A]=0.100 M\times e^{-6.3\times 10^{-6} s^{-1}\times 19.0\times 3600 s}

[A]=0.065 M

0.065 M is its molarity after a reaction time of 19.0 h.

b)

Initial concentration of [Co(NH_3)5Br]^{2+}= [A_o]=x

Final concentration of [Co(NH_3)5Br]^{2+} after t = [A]=(100\%-69\%) x=31\%x=0.31x

Rate constant of the reaction = k = 6.3\times 10^{-6} s^{-1}

The integrated law of first order kinetic is given as:

[A]=[A_o]\times e^{-kt}

0.31x=x\times e^{-6.3\times 10^{-6} s^{-1}\t}

t = 185,902.06 s = \frac{185,902.06 }{3600} hour = 51.64 hours ≈ 52 hours

In 52 hours [Co(NH_3)5Br]^{2+} will react 69% of its initial concentration.

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Why must reagent bottles be closed when not in use?
Katen [24]

Answer to your question.

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Based on the types of elements in the compound are there ionic or covalent? A. KCI B.NO2
Alex

B.

Explanation:

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7 0
3 years ago
Cl2 + 2OH− → Cl− + ClO− + H2O
Nataly_w [17]
Cl2(g) -------> Cl-(aq) + ClO-(aq) 

2e- + Cl2(g) -------> 2Cl-(aq) [reduction] 

4OH-(aq) + Cl2(g) -----------> 2ClO-(aq) + 2H2O(l) + 2e- [oxidation] 
______________________________________... 
2OH-(aq) + Cl2(g) --------> Cl-(aq) + ClO-(aq) + H2O(l)
4 0
3 years ago
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