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Mrac [35]
3 years ago
12

Which contributes to the polarity of a water molecule? A. a linear shape along with strong covalent bonds B. deflection of hydro

gen atoms by lone pairs of electrons C. no difference in the electronegativity of oxygen and hydrogen D. hydrogen bond formation between water molecules
Chemistry
2 answers:
vodomira [7]3 years ago
4 0

Here we have to choose the correct statement behind the polarity of the water molecule.

The polarity of the water molecules is due to the B. deflection of the hydrogen atoms by the lone pair of electrons.

The bonding of the water (H₂O) molecule is shown in the figure. There remain two lone pair of electrons on the oxygen atom. The oxygen atom has 6 valence electrons among which 2 are involved to make the covalent bond with two hydrogen atom.

The lone pair if electrons exerted lone pair-bond pair repulsion and H₂O has a bent structure as shown in the figure. In this way the dipole moment generated by oxygen and hydrogen cannot be nullified and it has a permanent dipole moment which leads the molecule to be polar in nature.

The water molecule is not linear in nature it has bent structure.

There is a huge difference of electronegativity between the hydrogen (H) and oxygen (O) atom. The oxygen atom is highly electronegative whereas the hydrogen atom is electropositive in nature.

The hydrogen bond formation is due to the fact the molecule is polar in nature.

lozanna [386]3 years ago
4 0

Answer:

<h3>The answer is B</h3>

Explanation:

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3 years ago
Design an experiment to collect data that supports the claim that a 1.0M NaCl solution is a homogenous mixture.
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The claim is that NaCl mixture is a homogeneous mixture.
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First, we need to prepare one molar solution of NaCl. To do so, we will dilute a mass of 58.44 grams (molar mass of NaCl) in 1 liter of water.
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We can notice that once the NaCl is diluted in water, all what you can see is a clear solution. You cannot see the separate particles of NaCl in water.
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Now, we will heat this solution until it boils and water starts evaporating. We will place a cold surface above the steam coming out from the boiling solution.

What we will observe is that when all the water evaporates, we can see white precipitate of NaCl in the bottom of the container. Examining the cold surface placed above the steam, we can see that the water has condensed on this surface.
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Based on this, we managed to use boiling, evaporation and condensation (physical methods) to restore the components of the solution separately.
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Based on observation I, observation II and the conclusion. we were able to prove that NaCl solution is a homogeneous mixture.
7 0
3 years ago
What is the number of moles in 3.0 X 10^24 atoms of Carbon
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4 0
1 year ago
A chemist fills a reaction vessel with 9.20 atm nitrogen monoxide (NO) gas, 9.15 atm chlorine (CI) gas, and 7.70 atm nitrosyl ch
ivanzaharov [21]

Answer:

The reactions free energy \Delta G = -49.36 kJ

Explanation:

From the question we are told that

      The pressure of (NO) is P_{NO} = 9.20 \ atm

      The  pressure of  (Cl) gas is  P_{Cl} = 9.15 \ atm

       The  pressure of nitrosly chloride (NOCl) is P_{(NOCl)} = 7.70 \ atm

The reaction is

              2NO_{(g)} + Cl_2 (g)    ⇆   2 NOCl_{(g)}

 From the reaction we can  mathematically evaluate the \Delta G^o (Standard state  free energy ) as

                    \Delta G^o = 2 \Delta G^o _{NOCl} -   \Delta G^o _{Cl_2}  - 2 \Delta G^o _{NO}

The Standard state  free energy for NO is  constant with a value  

                 \Delta G^o _{NO} = 86.55 kJ/mol

 The Standard state  free energy for Cl_2 is  constant with a value                  

             \Delta G^o _{Cl_2} = 0kJ/mol

 The Standard state  free energy for NOCl is  constant with a value

         \Delta G^o _{NOCl} =66.1kJ/mol

Now substituting this into the equation

        \Delta G^o = 2 * 66.1 - 0 - 2 * 87.6

                = -43 kJ/mol

The pressure constant is evaluated as

         Q =  \frac{Pressure \ of  \ product }{ Pressure  \ of \ reactant }

Substituting  values  

        Q = \frac{(7.7)^2 }{(9.2)^2 (9.15) } = \frac{59.29}{774.456}

           = 0.0765

The free energy for this reaction is evaluated as

           \Delta  G  =  \Delta  G^o  + RT ln Q

Where R is gas constant with a value  of  R = 8.314 J / K \cdot mol

          T is temperature in K  with a given value of  T = 25+273 = 298 K

   Substituting value

                \Delta  G  = -43 *10^{3} + 8.314 *298 * ln [0.0765]

                       = -43-6.36

                      \Delta G = -49.36 kJ

4 0
3 years ago
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