Answer:
Scandium
Titanium
Vanadium
Chromium
Manganese
Iron
Cobalt
Nickel
Copper
Zinc
Yttrium
Zirconium
Niobium
Molybdenum
Technetium
Ruthenium
Rhodium
Palladium
Silver
Cadmium
Lanthanum
Hafnium
Tantalum
Tungsten
Rhenium
Osmium
Iridium
Platinum
Gold
Mercury
Actinium
Rutherfordium
Dubnium
Seaborgium
Bohrium
Hassium
Meitnerium
Darmstadtium
Roentgenium
Copernicium
Explanation:
all of those are transition metals lol
Answer:
sulphuric acid and nitric acid
Explanation:
Answer: mixture
Explanation: they are heterogeneous mixtures not homogeneous
Answer:
0.4515 M
Explanation:
In case of titration , the following formula can be used -
M₁V₁ = M₂V₂
where ,
M₁ = concentration of acid ,
V₁ = volume of acid ,
M₂ = concentration of base,
V₂ = volume of base .
from , the question ,
M₁ = ? M
V₁ = 10.0 mL
M₂ = 0.100 M
V₂ = 45.15 mL
Using the above formula , the molarity of acid , can be calculated as ,
M₁V₁ = M₂V₂
M₁ * 10.0mL = 0.100 M * 45.15 mL
M₁ = 0.4515 M
Hence, the concentration of the acetic acid = 0.4515 M
It would be Ionic Compounds.