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3 years ago

Is number six correct? If so why???

Physics

1 answer:

Yuki888 [10]3 years ago

3 0

In question #5, the one where you have to label the three pictures,
all of your labels are correct !

Look at the 3rd picture, where the light is coming down slanted,
hitting some kind of surface, and bouncing away slanted.
You labelled that picture "reflection", and that's correct.

Now, look at the two angles marked in the picture .... the angle
between the arriving light and the surface, and the angle between
the departing light and the surface.

There is a statement in Science called the "Law of Reflection".
It simply says that those two angles are EQUAL.
I don't think we have to get into WHY right now. I think that
at this point, your class is just trying to teach you what the law says.
If you go on and study more physics in High School, then you'll learn
WHY the angles are equal.

If the light ray arrives and hits the mirror at a 40° angle,
then it'll leave the mirror at a 40° angle. It's that simple.

The two angles are the ones marked equal in the picture
where you wrote 'reflection'.

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A 5kg bag falls a verticle height of 10m before hitting the ground.

g100num [7]

Answer:

$u = 7m {s}^{ - 1}$

Explanation:

We know that when we don't have air friction on a free fall the mechanical energy (I will symbololize it with ME) is equal everywhere. So we have:

$me(1) = me(2)$

where me(1) is mechanical energy while on h=10m

and me(2) is mechanical energy while on the ground

Ek(1) + DynamicE(1) = Ek(2) + DynamicE(2)

Ek(1) is equal to zero since an object that has reached its max height has a speed equal to zero.

DynamicE(2) is equal to zero since it's touching the ground

Using that info we have

$m \times g \times h = \frac{1}{2} \times m \times u {}^{2} \\$

we divide both sides of the equation with mass to make the math easier.

$9.8 \times 10 = \frac{1}{2} \times u {}^{2} \\ \frac{98}{2} = u {}^{2} \\ u { }^{2} = 49 \\ u = 7$

7 0

3 years ago

Suppose a ceiling fan has a mass of 7.5 kg and is 9.7 m above the ground. What is the gravitational potential energy of the ceil

EleoNora [17]

The gravitational potential energy (G.P.E) of the ceiling fan is 712.95 Joules.

<u>Given the following data:</u>

Mass of ceiling fan = 7.5 kg

Height = 0.7 m

<u>Scientific data:</u>

Acceleration due to gravity = 9.8 $m/s^2$

To calculate the gravitational potential energy (G.P.E) of the ceiling fan:

<h3>What is gravitational potential energy?</h3>

Gravitational potential energy (G.P.E) can be defined as the energy that is possessed by an object or body due to its position (height) above planet Earth.

Mathematically, gravitational potential energy (G.P.E) is given by this formula;

$GPE = mgh$

<u>Where:</u>

G.P.E is the gravitational potential energy.

m is the mass of an object.

g is the acceleration due to gravity.

h is the height of an object.

Substituting the given parameters into the formula, we have;

$GPE = 7.5 \times 9.8 \times 9.7$

GPE = 712.95 Joules.

Read more on potential energy here: brainly.com/question/8664733

8 0

2 years ago

How does the speed of a wave relate to its wavelength and frequency?*

grigory [225]

Answer: Wavespeed (V) = Frequency F x wavelength λ (V = F λ)

Explanation:

The wavespeed is the distance covered by a wave in one second. It is measured in metre per second, and represented by the symbol V. It is directly proportional to the wavelength and frequency

i.e Velocity (V) = Frequency F x wavelength λ

V = F λ

For instance:

Assume wavelength (λ)= 20 m

Frequency = 10 Hz.

To get the wavespeed, use the formula

V = F λ

V = 20 metres x 10 hertz

V = 200 metres per second

Thus, the wave travels at a speed of 200 metres per second

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Kitty [74]

Answer:

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Explanation:

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AlexFokin [52]

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