A students walks one hour. She walks 4 blocks east and 2 blocks west. Her average velocity is?
1 answer:
Let us consider the following figure
<em>figure</em><em> </em><em>is</em><em> </em><em>in</em><em> </em><em>pict</em><em>ure</em>
So, his/her total displacement = 2 blocks.
total time = 1 hour
Average Velocity
= Total displacement/ total time
= 2 blocks/ 1 hour
= 2 blocks/ h
So, her/his average velocity is 2 blocks per hour.
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Answer : The value of is 286.2 J and 286.2 J respectively.
Explanation : Given,
Moles of sample = 0.877 mol
Change in temperature = 15.7 K
First we have to calculate the heat absorbed by the system.
Formula used :
where,
q = heat absorbed by the system = ?
n = moles of sample = 0.877 mol
= Change in temperature = 15.7 K
= heat capacity at constant volume of
(diatomic molecule) =
R = gas constant = 8.314 J/mol.K
Now put all the given value in the above formula, we get:
Now we have to calculate the change in internal energy of the system.
As we know that, work done is zero at constant volume. So,
Therefore, the value of is 286.2 J and 286.2 J respectively.
Answer:
a= 23.65 ft/s²
Explanation:
given
r= 14.34m
ω=3.65rad/s
Ф=Ф₀ + ωt
t = Ф - Ф₀/ω
= (98-0)×/3.65
98°= 1.71042 rad
1.7104/3.65
t= 0.47 s
r₁(not given)
assuming r₁ =20 in
r₁ = r₀ + ut(uniform motion)
u = r₁ - r₀/t
r₀ = 14.34 in= 1.195 ft
r₁ = 20 in = 1.67 ft
= (1.667 - 1.195)/0.47
0.472/0.47
u= 1.00ft/s
acceleration at collar p
a=rω²
= 1.67 × 3.65²
a = 22.25ft/s²
acceleration of collar p related to the rod = 0
coriolis acceleration = 2ωu
= 2× 3.65×1 = 7.3 ft/s²
acceleration of collar p
= 22.5j + 0 + 7.3i
√(22.5² + 7.3²)
the magnitude of the acceleration of the collar P just as it reaches B in ft/s²
a= 23.65 ft/s²