1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Novay_Z [31]
3 years ago
8

For a reaction Y → X with a very high equilibrium constant, K, which of the following is true? You can refer to the following tw

o equations in formulating your answer.$$$$Choose one:A. The standard free-energy change is large and positive.B. The amount of product and substrate are equal at equilibrium.C. The forward reaction rate greatly exceeds the reverse reaction rate at equilibrium.D. The amount of product will be higher than the amount of substrate at equilibrium.
Chemistry
1 answer:
Dafna11 [192]3 years ago
8 0

Answer:The amount of product will be higher than the amount of substrate at equilibrium

Explanation:

Recall that the equilibrium constant K depends on the amounts of reactants and products present in the system at equilibrium.

Considering the equation; K = [X]/[Y], as the concentration of X increases above that of Y, the equilibrium constant K becomes very high, hence the answer above.

You might be interested in
Which characteristic do electronegativity differences indicate about reactions between atoms
emmasim [6.3K]
O valence electron number is the answer
6 0
2 years ago
What are 5 physical changes in matter
Gennadij [26K]

Answer:

cutting, bending, dissolving, freezing, and boiling

Explanation:

A physical change is a change in one or more physical properties of matter without any change in chemical properties. In other words, matter doesn't change into a different substance in a physical change. Examples of physical change include but are not limited to, from solid to liquid or from liquid to gas are also physical changes.

3 0
2 years ago
4. DBearded waste of Co-60 must be stored until it is no longer radioactive. Cobalt-60
Bingel [31]

464 g radioisotope was present when the sample was put in storage

<h3>Further explanation</h3>

Given

Sample waste of Co-60 = 14.5 g

26.5 years in storage

Required

Initial sample

Solution

General formulas used in decay:  

\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}

t = duration of decay  

t 1/2 = half-life  

N₀ = the number of initial radioactive atoms  

Nt = the number of radioactive atoms left after decaying during T time  

Half-life of Co-60 = 5.3 years

Input the value :

\tt 14.5=No.\dfrac{1}{2}^{26.5/5.3}\\\\14.5=No.\dfrac{1}{2}^5\\\\No=\boxed{\bold{464~g}}

8 0
2 years ago
Which is an example of poor safety practices when working outdoors
kati45 [8]

Answer:

C

Explanation:

u can't touch a chemical with bare skin

7 0
3 years ago
Read 2 more answers
What trend would you predict for the next ten years for each region?
Artemon [7]
The new trend will probably be the technology that's in that certain year. Like the trend in the modern days are all electronics or will have to do with electronics. Hope this helps! :) Pls mark me as the BRAINLIEST!!!
3 0
3 years ago
Other questions:
  • Express 578,000 in scientific notation
    10·1 answer
  • Why hf has higher boiling point greater than nh3
    13·1 answer
  • All please <br>guys help me <br>please ​
    9·1 answer
  • Two chemicals A and B are combined to form a chemical C. The rate, or velocity, of the reaction is proportional to the product o
    9·1 answer
  • What was Ernest Rutherford's experiment?​
    14·1 answer
  • How many particles of CuCr2O7 are present in a 64.5 gram sample?
    10·1 answer
  • What is the value for AG at 100 Kif AH = 27 kJ/mol and AS = 0.09 kJ/(mol-K)?
    7·1 answer
  • A construction worker uses a pulley and a rope to
    13·1 answer
  • Which other element is most likely to be a nonreactive gas?
    8·2 answers
  • Which of the following is a stock exchange in the United States?(1 point)
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!