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natima [27]
3 years ago
15

What are four ways that rocks are physically weathered to form soil

Chemistry
2 answers:
aev [14]3 years ago
8 0
Rain wears it down, water seeps into cracks and turns to ice; creating bigger cracks, it can expand and contract due to temperatures rising and lowering and plants can grow on it so the roots break down the rocks to make room
Margaret [11]3 years ago
4 0
-The water washes it causing it to break
-How hot or cold it is matters.
-ice can get into cracks which causes it to crack
-????
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During a chemical reaction, an iron atom became the ion Fe2+. What happened to the iron atom?
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The Iron atom lost two electrons to become the Fe2+ ion. This is referred to as oxidation.
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When the temperature of a 3. 0-l sample of a gas is dropped from 200°c to 100°c, what will be the final volume of the gas sample
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P1V1T1=P2V2T2 Add 273 to convert degrees Celsius to Kelvin:

∴200×25/298=250×V2/273, ∴V2=200×25×273/298×250, ∴V2=18.32L

<h3>Where is the volume equation?</h3>

The basic formula for volume is length, breadth, and height, as opposed to length, width, and height for the area of a rectangular shape. The calculation is unaffected by how you refer to the various dimensions; for instance, you can use "depth" instead of "height."

<h3>What is chemistry using volume units?</h3>

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1 year ago
Cr2o2−7(aq)+i−(aq)→cr3+(aq)+io−3(aq) (acidic solution) express your answer as a chemical equation. identify all of the phases in
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What is a potential risk of genetically modified food?
Ivahew [28]

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A sample of N2 gas in a flask is heated from 27 Celcius to 150 Celcius. If the original gas is @ pressure of 1520 torr, what is
Romashka [77]

Answer:

\large \boxed{\text{B.) 2.8 atm}}

Explanation:

The volume and amount are constant, so we can use Gay-Lussac’s Law:

At constant volume, the pressure exerted by a gas is directly proportional to its temperature.

\dfrac{p_{1}}{T_{1}} = \dfrac{p_{2}}{T_{2}}

Data:

p₁ = 1520 Torr; T₁ =   27 °C

p₂ = ?;               T₂ = 150 °C

Calculations:

(a) Convert the temperatures to kelvins

T₁ = (  27 + 273.15) K = 300.15 K

T₂ = (150 + 273.15) K = 423.15 K

(b) Calculate the new pressure

\begin{array}{rcl}\dfrac{1520}{300.15} & = & \dfrac{p_{2}}{423.15}\\\\5.064 & = & \dfrac{p_{2}}{423.15}\\\\5.064\times423.15&=&p_{2}\\p_{2} & = & \text{2143 Torr}\end{array}\\

(c) Convert the pressure to atmospheres

p = \text{2143 Torr} \times \dfrac{\text{1 atm}}{\text{760 Torr}} = \textbf{2.8 atm}\\\\\text{The new pressure reading will be $\large \boxed{\textbf{2.8 atm}}$}

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3 years ago
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