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3 years ago

How much of a 10 M solution is needed to make 1 liter of a 1 M solution

Chemistry

1 answer:

mylen [45]3 years ago

5 0

Answer:

0.1 L

Explanation:

M₁ × V₁ = M₂ × V₂

10M × V₁ = 1M × 1L

V₁ = 0.1 L

I hope this helps :)

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What is the density of object C? Does it sink or float in water?

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Answer:

0.96 g/cm3, and it will float!

Explanation:

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By looking at the graph you can see that Object C has a mass of ~24 grams and a volume of ~25 cm3

Density = Mass/Volume -> 24 grams/25 cm3 = 0.96 g/cm3

Density of water is 1 g/cm3

Object C is less dense than water and therefore will float (just barely, though)

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Which landform is located at the mouth of the river?

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Min increases the temperature of a gas in an expandable container. If she keeps the pressure constant, what will happen to the v

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The volume will remain the same.

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Be sure to answer all parts. The percent by mass of bicarbonate (HCO3−) in a certain Alka-Seltzer product is 32.5 percent. Calcu

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Answer : The volume of $CO_2$ will be, 514.11 ml

Explanation :

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First we have to calculate the mass of $HCO_3^-$ in tablet.

$\text{Mass of }HCO_3^-\text{ in tablet}=32.5\% \times 3.79g=\frac{32.5}{100}\times 3.79g=1.23175g$

Now we have to calculate the moles of $HCO_3^-$ .

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Now we have to calculate the moles of $CO_2$ .

From the balanced chemical reaction, we conclude that

As, 1 mole of $HCO_3^-$ react to give 1 mole of $CO_2$

So, 0.0202 mole of $HCO_3^-$ react to give 0.0202 mole of $CO_2$

The moles of $CO_2$ = 0.0202 mole

Now we have to calculate the volume of $CO_2$ by using ideal gas equation.

$PV=nRT$

where,

P = pressure of gas = 1.00 atm

V = volume of gas = ?

T = temperature of gas = $37^oC=273+37=310K$

n = number of moles of gas = 0.0202 mole

R = gas constant = 0.0821 L.atm/mole.K

Now put all the given values in the ideal gas equation, we get :

$(1.00atm)\times V=0.0202 mole\times (0.0821L.atm/mole.K)\times (310K)$

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