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2 years ago

6

Two point charges, initially 3 cm apart, are moved to a distance of 1 cm apart. By what factor does the resulting electric force

between them change?
A. 3
B. 1/9
C. 1/3
D. 9

1 answer:

Solnce55 [7]2 years ago

6 0

The answer is B (1/9).

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Answer:

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Explanation:

Given

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See attachment for connection

Required

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First, we calculate the total capacitance (C1) in (a):

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$T\ \alpha\ C$

Convert to equation

$T\ =kC$

Make k the subject

$k = \frac{T}{C}$

$k = \frac{T_1}{C_1} = \frac{T_2}{C_2}$

$\frac{T_1}{C_1} = \frac{T_2}{C_2}$

Make T2 the subject

$T_2 = \frac{T_1 * C_2}{C_1}$

Substitute values for T1, C1 and C2

$T_2 = \frac{1.48 * \frac{2}{5}C}{C}$

$T_2 = \frac{1.48 * \frac{2}{5}}{1}$

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