Force required is 100 N
<u>Given that;</u>
Rate of acceleration = 5 m/s²
Mass of object = 20kg
<u>Find:</u>
Force required
<u>Computation:</u>
Force = Mass × Acceleration
Force required = Rate of acceleration × Mass of object
Force required = 20 × 5
Force required = 100 N
Learn more:
brainly.com/question/17506203?referrer=searchResults
We learned that We are in the disk of the Galaxy, about 5/8 of the way from the center.
<h3>What is the work of Harlow Shapley?</h3>
Shapley, who was headquartered in Boulder, Colorado, used Cepheid variable stars to estimate the size of the Milky Way Galaxy and its position relative to the Sun. In 1953, he published his "liquid water belt" theory, today known as the concept of a livable zone.
There are many stars, grains of dust, and gas in the Milky Way. It is known as a spiral galaxy because, from the top or bottom, it would appear to be whirling like a pinwheel. About 25,000 light-years from the galaxy's nucleus, the Sun is situated on one of the spiral arms.
Approximately 5/8 of the way from the galaxy's nucleus, we are in the disc. William Herschel believed that the Sun and Earth were about in the middle of the vast cluster of stars known as the Milky Way.
To learn more about Harlow Shapley's original estimate go to - brainly.com/question/28145909
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Explanation:
Constant speed means that the object is covering equal distance in equal interval of time. The motion is called uniform motion for such case. In this problem, it is given that an object is moving with a constant speed of 8 m/s. It means that it does not change its speed. It is moving with a single speed constantly.
We can say that it moves 8 meters every second or 800 cm every second.
A. The proeutectoid phase is Fe₃c because 0.95 wt/c is greater than the eutectoid composition which is 0.76 wt/c
b. We determine how much total territe and cementite form, we apply the lever rule expressions yields.
Wx = (fe₃c-co/cfe₃ c-cx = 6.70- 0.95/6.70- 0.022 = 0.86
The total cementite
Wfe₃C = 10-Cx/ Cfe₃c -Cx = 0.95 - 0.022/6.70 - 0.022 = 0.14
The total cementite which is formed is
(0.14) × (3.5kg) = 0.49kg
c. We calculate the pearule and the procutectoid phase which cementite form the equation
Ci = 0.95 wt/c
Wp = 6.70 -ci/6.70 - 0.76 = 6.70 -0.95/6.70 - 0.76 = 0.97
0.97 corresponds to mass.
W fe₃ C¹ = Ci - 0.76/5.94 = 0.03
∴ It is equivalent to
(0.03) × (3.5) = 0.11kg of total of 3.5kg mass.
Answer:
The first one (60%)
Explanation:
The first one converts 15% more energy than the other one. Therefore, it is more efficient.
Hope this helps!
