Every second it travels 2 meters and it traveled 3 so (2 x 3) would be 6meters it traveled
Answer:
- Contact 1 with 3
, initial charge of 1.8 C.
- contact 1 with 2 and then 1 with 3
, first body should have 3.6 C
Explanation:
The excess charge on a body is distributed evenly throughout the body.
We can have two different configurations:
- Contact 1 with 3
When the third body was touched with the first, the initial charge was distributed between the two, so that when each one separated, it had half the charge, in this configuration the first body should have an initial charge of 1.8 C.
- contact 1 with 2 and then 1 with 3
Another possible configuration of the exercise is that the first body touches the second and the charge decrease to the half and then touches the third where it again decreases by half, so that the first body only gives it every ¼ of its initial load.
Therefore in this configuration if the third body has a load of 0.9C the first body should have 3.6 C
Answer:
The final velocity of the car is 36 m/s.
Explanation:
Given;
initial velocity of the car, u = 20 m/s
time of the car acceleration, t = 4 s
acceleration of the car, a = 4 m/s²
the final velocity of the car is calculated as;
v = u + at
where;
v is the final velocity of the car
v = 20 + (4 x 4)
v = 36 m/s
Therefore, the final velocity of the car is 36 m/s.
