Answer:
1.72 x 10³ N.
Explanation:
When a charge is split equally and placed at a certain distance , maximum electrostatic force is possible.
So the charges will be each equal to
31/2 = 15.5 x 10⁻⁶ C
F = K Q q / r²
= 
= 1.72 x 10³ N.
In the above case we can say that power given by external agent to pull the rod must be equal to the power dissipated in the form of heat due to magnetic induction.
Part a)
when we pull the rod with constant speed then power required will be product of force and velocity
here we will have

P = 4 W
v = 4 m/s
now we will have


So external force required will be 1 N
PART B)
now in order to find magnetic field strength we can say

here we know that induced EMF in the wire is E = vBL
so power due to induced magnetic field is given by


by solving above equation we will have

Answer:
Explanation:
we know that
s=vt here v is the speed and s is distance covered by the signals
given data
v=3*10^8
t=10 min we have to convert it into seconds
1 minute=60 seconds
so
10 minutes =10*60/1 =600 seconds
now putting the value of v and t we can find the value of s
s=vt
s=3*10^8*600
s=1.8*10^11m
i hope this will help you
<h2>
a)Time taken is 12.90 seconds</h2><h2>
b) Time taken is 72.46 seconds</h2>
Explanation:
Let east be positive x axis and north be positive y axis
Speed = 1.60 m/s in a direction that is 15.0° north of east.
Speed, v = 1.60 cos 15 i + 1.60 sin 15 j = 1.55 i + 0.414 j m/s
a) We need to find time taken to travel 20 m along east
Speed along east = 1.55 m/s
Distance = Speed x Time
20 = 1.55 x Time
Time = 12.90 seconds
Time taken is 12.90 seconds
b) We need to find time taken to travel 30 m along north
Speed along north = 0.414 m/s
Distance = Speed x Time
30 = 0.414 x Time
Time = 72.46 seconds
Time taken is 72.46 seconds