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4 years ago

All man-made and most carbon-based compunds are

Chemistry

2 answers:

inessss [21]4 years ago

6 0

Explanation:

Organic compounds are the compounds that consists of chains of carbon atoms.

Most of the compound present in nature are made up of carbon atoms. And it is true that carbon has more number of compounds as compared to any other element.

For example, refined oil that we use for cooking has carbon atoms and it is a man-made product.

Therefore, we can conclude that all man-made and most carbon-based compounds are organic.

Black_prince [1.1K]4 years ago

5 0

Artificial compounds such as charcoal and fire

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28. Scott travels north 5 miles and then goes south 3 miles before coming back due north for an additional 2 miles. What is his

liubo4ka [24]

Answer:

4 miles north

Explanation:

Initially Scott travels 5 miles north at this point his displacement is 5 miles toward north

then he goes 3 miles south. which makes his displacement 2 miles (5 - 3 = 2) towards north as north and south are opposite directions.

finally he travels 2 miles due north.so his final displacement is

2 miles + 2 miles = 4 miles towards north direction

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3 years ago

What are the two functional group present in the molecule

dedylja [7]

Answer:

carboxyl group (COOH) and amines

Explanation:

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3 years ago

What is the frequency and energy per quantum (in Joules) of :

viktelen [127]

(a) f = 5.00 × 10²⁰ Hz, E = 3.32 × 10⁻¹³ J;

(b) f = 1.20 × 10¹⁰ Hz, E = 7.96 × 10⁻²⁴J.

<h3>Explanation</h3>

What's the similarity between a gamma ray and a microwave?

Both gamma rays and microwave rays are electromagnetic radiations. Both travel at the speed of light at $3.00 \times 10^{8}\;\text{m}\cdot\text{s}^{-1}$ in vacuum.

$f = \dfrac{c}{\lambda}$

where

f is the frequency of the electromagnetic radiation,
c is the speed of light, and
$\lambda$ is the wavelength of the radiation.

(a)

Convert all units to standard ones.

$\lambda = 0.600\;\text{pm} = 0.600 \times 10^{-12} \;\text{m}$ .

The unit of $f$ shall also be standard.

$f = \dfrac{c}{\lambda} = \dfrac{3.00\times 10^{8}\;\text{m}\cdot\text{s}^{-1}}{0.600\times 10^{12}\;\text{m}} = 5.00 \times 10^{20}\;\text{s}^{-1}= 5.00\times 10^{20}\;\text{Hz}$ .

For each particle,

$E = h\cdot f$ ,

where

$E$ is the energy of the particle,
$h$ is the planck's constant where $h = 6.63\times 10^{-34}\;\text{J}\cdot\text{s}^{-1}$ , and
$f$ is the frequency of the particle.

$E = h \cdot f = 6.63\times10^{-34}\;\text{J}\cdot\text{s}\times 5.00\times 10^{20}\;\text{s}^{-1} = 3.32\times10^{-13}\;\text{J}$ .

(b)

Try the steps in (a) for this beam of microwave with

$\lambda = 2.50 \;\text{cm} = 2.50\times 10^{-2}\;\text{m}$ .

Expect the following results:

$f = 1.20\times 10^{10}\;\text{Hz}$ , and
$E = 7.96\times 10^{-24}\;\text{J}$ .

4 0

3 years ago

PLEASE HELP!!

Serggg [28]

Iron, but there are some amounts of other dense elements like gold, platinum, and uranium.

5 0

3 years ago

A sample of propane (C3H8) has a mass of 0. 47 g. The sample is burned in a bomb calorimeter that has a mass of 1. 350 kg and a

Nady [450]

The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.

The specific heat has been defined as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree Celsius.

The specific heat has been expressed as:

$q=mc\Delta T$

<h3 /><h3>Computation for the heat absorbed</h3>

The iron and calorimeter are in side the closed system. Thus, the energy released by the sample, has been equivalent to the energy absorbed by the calorimeter.

$q_{released}=q_{absorbed}\\
q_{released}=m_{calorimeter}\;c_{calorimeter}\;\Delta T$

The given mass of calorimeter has been, $m_{calorimeter}=1350\;\rm g$

The specific heat of the calorimeter has been, $c_{calorimeter}=5.82\;\rm J/g^\circ C$

The change in temperature of the calorimeter has been, $\Delta T=2.87^\circ \rm C$

Substituting the values for heat released:

$q_{released}= 1350\;\text g\;\times\;5.82\;\text J/\text g^\circ \text C\;\times\;2.87^\circ \text C\\
q_{released}=22,549.5\;\text J\\
q_{released}}=22.54\;\rm kJ$

The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.

Learn more about specific heat, here:

brainly.com/question/2094845

6 0

3 years ago