Answer:

Explanation:
From the question we are told that:
Pressure 
Temperature 
Volume 
Heat Produced 
Generally the equation for ideal gas is mathematically given by



Therefore


Since
Heat of combustion of Methane=889 kJ/mol
Heat of combustion of Propane=2220 kJ/mol
Therefore

Comparing Equation 1 and 2 and solving simultaneously




Therefore
Mole fraction 0f Methane is mathematically given as



Answer:
C. 3CO(g) + Fe2O3(s)
Explanation:
The substance(s) to the hath left of the arrow in a chemical equation art hath called reactants. A reactant is a substance yond is presenteth at the starteth of a chemical reaction. The substance(s) to the right of the arrow art hath called products. A product is a substance yond is presenteth at the endeth of a chemical reaction
So in this example, 3CO(g) + Fe2O3(s) art the reactants.
The 2Fe(S) + 3CO2(G) art the products.
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Answer: weigh is m = n × M = 2.87 mol × 58.44 g/mol
Explanation: mass = amount of substance × molar mass
M((NaCl) = 22.99 +35.45
Answer:
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