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adoni [48]
3 years ago
7

((HELP!!!))

Physics
2 answers:
STatiana [176]3 years ago
7 0
The correct answer would be  A. The forces are equal.
RideAnS [48]3 years ago
3 0
Hey there,

Your question states: <span>How is the weight of water displaced by a floating cork related to the buoyant force on the cork?

That key word here is (float). If the cork is floating, this would include that they both would have the equal balance of force. If they did not, it would most likely sink to the bottom. 

Your correct answer is </span><span>The forces are equal.</span>
You might be interested in
If you climb to the top of Mt. Everest, you will be 8850 m (about 5.50 mi) above sea level.
Umnica [9.8K]

Answer:

9.773m/s2

Explanation:

Given,

h=8848m

The value of sea level is 9.08m/s2

So,

Let g′ be the acceleration due to the gravity on the Mount Everest.

g′=g(1−h2h)

=9.8(1−640000017696)

=9.8(1−0.00276)

9.8×0.99724

=9.773m/s2

Thus, the acceleration due to gravity on the top of Mount Everest is =9.773m/s2

Hope it helped!!!

5 0
3 years ago
I NEED HELP ASAPPPP!!
Juli2301 [7.4K]

Increase in wavelength will cause decrease in frequency. When wavelength doubles, the frequency of the wave will reduce to half of its value.

<h3>WAVE SPEED</h3>

The wave speed is the product of wave frequency and its wavelength.

v = f⋅λ

  • v = the speed of a wave
  • f = frequency
  • λ = wavelength

For example, if a wave has a frequency of 120 Hz and a wavelength of 5m, it would have a speed of 600 m/s.

if the wavelength is increased to 10m but the speed stays the same at 600 m/s. That is,

λ = 10m

v = 600 m/s

v = f⋅λ

Substitute f and v into the formula

600 = 10f

f = 600 / 10

f = 60 m

The frequency of the wave is reduced to half of its value.

Learn more about wave speed here: brainly.com/question/2847127

8 0
2 years ago
Calculate the density of Saturn. Show your work. How does it compare with the density of water? Explain how this can be.
stepladder [879]

Answer:

The density of Saturn is 686.81 kg/m³.

Explanation:

Mass of Saturn,  m=5.68\times 10^{26}\ kg  

Volume of Saturn, V=8.27\times 10^{23}\ m^3

Density of Saturn is given by its mass divided by its volume i.e.

d=\dfrac{m}{V}

d=\dfrac{5.68\times 10^{26}}{8.27\times 10^{23}}

d=686.81\ kg/m^3

So, the density of Saturn is 686.81 kg/m³.

The density of water is 1000 kg/m³. It is clear that the density of Saturn is less than water.

4 0
3 years ago
The frequency and wavelength of EM waves can vary over a wide range of values. Scientists refer to the full range of frequencies
mestny [16]

Complete question is;

The frequency and wavelength of EM waves can vary over a wide range of values. Scientists refer to the full range of frequencies that EM radiation can have as the electromagnetic spectrum. Electromagnetic waves are used extensively in modern wireless technology. Many devices are built to emit and/or receive EM waves at a very specific frequency, or within a narrow band of frequencies. Here are some examples followed by their frequencies of operation:

garage door openers: 40.0 MHz

standard cordless phones: 40.0 to 50.0 MHz

baby monitors: 49.0 MHz

FM radio stations: 88.0 to 108 MHz

cell phones: 800 to 900 MHz

Global Positioning System: 1227 to 1575 MHz

microwave ovens: 2450 MHz

wireless internet technology: 2.4 to 2.6 GHz

Which of the following statements correctly describe the various applications listed above? Check all that apply.

a.) All these technologies use radio waves, including low-frequency microwaves.

b.) All these technologies use radio waves, including high-frequency microwaves.

c.) All these technologies use a combination of infrared waves and high-frequency microwaves.

d.) Microwave ovens emit in the same frequency band as some wireless Internet devices.

e.) The radiation emitted by wireless Internet devices has the shortest wavelength of all the technologies listed above.

f.) All these technologies emit waves with a wavelength in the range of 0.10 to 10.0 m.

g.) All the technologies emit waves with a wavelength in the range of 0.01 to 10.0 km.

Answer:

B, D, E, F are the correct statements.

Explanation:

Looking at the options;

A) This is true because radio waves are electromagnetic radiation being used today in television, mobile phones, radios and other areas of communication technologies. And the examples given to us fall in the category of technologies that use radio waves.

B) microwaves usually have long wavelengths and low frequencies. However, sometimes they could have high frequencies usually more than radio waves. Thus, this option is correct.

C) This option is wrong because it's not all the listed technologies that use combination of infrared waves and high-frequency microwaves.

D) we are given the frequency of microwave ovens as 2450 MHz.

Converting to GHz gives; 2.45 GHz.

We are told that wireless internet technology has frequency between 2.4 to 2.6 GHz. Thus, microwave frequency falls in the same range as wireless internet technology and thus the statement is true.

E) we know that wavelength is inversely proportional to frequency. This means that the higher the frequency, the shorter the wavelength.

In the frequencies given to us, wireless internet technology have the highest frequency which means they have the shortest wavelength. The statement is true.

F) from the frequencies given to us, the smallest is garage door openers = 40.0 MHz = 40 × 10^(6) Hz while the biggest is 2.6 GHz = 2.6 × 10^(9) Hz

Formula for wavelength is;

Wavelength = speed of light/frequency

Speed of light = 3 × 10^(8) m/s

Thus;

Wavelength = (3 × 10^(8))/(40 × 10^(6))

Or wavelength = (3 × 10^(8))/(2.6 × 10^(9))

So,wavelength = 7.5 m or 0.12 m

This falls into the given range of 0.10 to 10.0 m.

Thus, the statement is true.

8 0
3 years ago
Calculate the energy per photon and the energy per mole of photons for radiation of wavelength (a) 200 nm (ultraviolet), (b) 150
VMariaS [17]

Answer: a. E =9.9*EXP(-19)J

1 mole E= 596178J

b. E= 1.32*EXP(-15)J, 1 mole E=795MegaJ

c. E= 1.98*EXP(-23)J

1 mole E = 11.9J

Explanation: The Energy of a photon E, the wavelength are related by

E= h*c/wavelength

h is the Planck's constant 6.6*EXP(-34)J.s

c is speed of light 3*EXP(8)m/s

h*c=1.98*EXP(-25)

Now let's solve

a. E = h*c/wavelength

= h*c/(200*EXP(-9)m

=9.9*EXP(-19)J

1 mole of a photon contian 6.022*EXP(23)photons by advogadro

Now to get the energy of 1 mole of the photon we have

9.9*EXP(-19)*6.023*EXP(23)

=596178J

b. E=h*c/150*EXP(-12)m

=1.32*EXP(-15)J

1 mole will have

1.32*EXP(-15)*6.022*EXP(23)J

=795*EXP(6)J

c. E= h*c/1*EXP(-2)m

=1.98*EXP(-23)J

1 mole of the photon will have

1.98*EXP(-23)J *6.022*EXP(23)

= 11.9J.

You will notice that the longer the wavelength of the photon the lesser the Energy it as.

NOTE: EXP represent 10^

8 0
4 years ago
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