Answer:
K2CrO4
Explanation:
To find the empirical formula, we need to divide each element by its atomic mass. The atomic masses of potassium, chromium and oxygen are 39.0983, 51.9961 and 15.999 respectively. We make the divisions as follows:
K = 1.04/39.0983 = 0.027
Cr = 0.70/51.9961 = 0.013
O = 0.86/15.999 = 0.054
We now divide by the smallest which is the number of moles of the Chromium
K = 0.027/0.013 = 2
Cr = 0.013/0.013 = 1
K = 0.054/0.013 = 4 approximately
The empirical formula is thus:
K2CrO4
Answer:
NaH(s) + H2O(l) ------> NaOH(aq) + H2(g)
2Al(s) + 3Cl2(g) -----> 2AlCl3(s)
Explanation:
The rule of thumb in balancing chemical reaction equation is that the number of atoms of each element on the reactant side must be the same as the number of atoms of the same element on the product side. Only then can any reaction equation be seen as balanced.
For example there are two aluminum atoms on both sides of the reaction equation and six chlorine atoms on both sides of the reaction equation. Hence the reaction equation is balanced.
The balanced chemical reaction is expressed as:
M + F2 = MF2
To determine the moles of the element fluorine present in the product, we need to determine the moles of the product formed from the reaction and relate this value to the ratio of the elements in MF2. We do as follows:
moles MF2 produced = 0.600 mol M ( 1 mol MF2 / 1 mol M ) = 0.600 mol MF2
molar mass MF2 = 46.8 g MF2 / 0.6 mol MF2 = 78 g/mol
moles MF2 = 46.8 g ( 1 mol / 78 g ) = 0.6 mol
moles F = 0.6 mol MF2 ( 2 mol F / 1 mol MF2 ) = 1.2 moles F
<h3>
Answer:</h3>
318.405 g
<h3>
Explanation:</h3>
We are given;
- Volume of K₃PO₄ solution to be prepared as 750.0 mL or 0.75 L
- Molarity of the solution to be prepared as 2.00 M
We are required to determine the mass of K₃PO₄ to be measured.
<h3>Step 1: Determine the number of moles of K₃PO₄</h3>
Molarity = Moles ÷ Volume
Rearranging the formula;
Number of moles = Molarity × Volume
Therefore;
Moles of K₃PO₄ = 2.00 M × 0.75 L
= 1.5 moles
<h3>Step 2: Determine the mass of K₃PO₄ to be measured</h3>
Mass = Number of moles × Molar mass
Molar mass of K₃PO₄ = 212.27 g/mol
Therefore;
Mass of K₃PO₄ = 1.5 moles × 212.27 g/mol
= 318.405 g
Therefore, the mass of K₃PO₄ that should be weighed is 318.405 g
You could say that hydrogen and Oxygen molecules are similar in that their chemical formula is H2 and O2. That means there are 2 "atoms" per molecule. I don't know how to put water into this because water molecules are quite different from H2 and O2. Even the intramolecular forces are quite different.
H2 and O2 are different in their masses per molecule.One is quite a bit heavier than the other. They can be quite explosive if they are put in the same container. I once heard a NASA engineer say that Hydrogen is a "real snake" to handle. It is used for rocket fuel. Both are compressed a great deal.
