Answer:
The 20th century saw huge advances in our understanding and use of the nucleus. For instance, in 1939 scientists Otto Hahn, Lise Meitner and Otto Frisch discovered nuclear fission – a process by which radioactive materials release energy when they are induced to split.
Realising the huge amount of energy that such a reaction produces, scientists were tasked with developing this new knowledge initially for harm in nuclear weapons. Just six years after fission’s discovery, it was harnessed in the atom bombs that destroyed the Japanese cities Hiroshima and Nagasaki, and controversially ended the Second World War. Later, much more powerful hydrogen bombs were developed that combined fission with the process powering the Sun – fusion.
Hope this helps! PLEASE GIVE ME BRAINLIEST!!!!! =)
Answer: 2 lone pairs, square planar
Explanation:
Using the VSEPR ( Valence Shell Electron Pair Repulsion)Theory
To calculate the number of lone pairs electron can be done using the formula;
Number of electrons = ½ (V+N-C+A)
V mean valency of the central atom
N means number of monovalent bonding atoms
C means charge on cation
A means charges on anion
Therefore, to calculate the number of lone pair electron C=A=0;
Number of electrons = ½ (8+4) = 12/2 = 6
Number of bonding pair = 4
Number of lone pairs of electron = 6-4 = 2
The hybridrization of the compound is sp3d2 because the number of electrons around the central atom is 6.
The geometry of the compound is square planar and this is because of the repulsion between the bonding pair of electrons and lone pair of electrons which causes the lone pair of electrons to lie in a perpendicular plane in order to acquire stability.
Answer:
not quite sure what you meant by the question but I think the answer you're looking for is biomass? not sure though
Answer: The final pressure is 34.48kPa
Initial Pressure P1 = 55.16kPa
Initial Volume V1 = 0.500L
Final Pressure P2 = ?
Final Volume V2 = 0.800L
Boyle's law P1V1 = P2 V2
P2 = P1V1/V2
P2 = 55.16*0.5/0.8
P2 = 34.48kPa
Answer:
Element Symbol Mass Percent
Cuprum Cu 66.464%
Sulfur S 33.537%
Explanation:
I got this out of my module, sorry if it's wrong but i am pretty sure 97% this is correct!
