a family consumes 2.5 gallons of milk per week. how many liters of milk do they need to buy for 1 week?

A sample of methane gas has a volume of 10 l at a pressure of 1.5 atm and a temperature of 20 °c. what volume does the gas occup

a_sh-v [17]

We can use combined gas laws to solve for the volume of the gas
$\frac{PV}{T}$
where P - pressure, V - volume , T - temperature and k - constant
$\frac{P1V1}{T1} = \frac{P2V2}{T2}$
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
T1 - temperature in Kelvin - 20 °C + 273 = 293 K
T2 - 40 °C + 273 = 313 K
substituting the values
$\frac{1.5 atm*10L}{293 K} = \frac{0.9 atm*V}{313K}$
V = 17.8 L
volume of the gas is 17.8 L

7 0

3 years ago

How do acquired characteristics differ from adaptations

SOVA2 [1]

Answer:

acquired traits are traits that organisms develops over a lifetime. adaptation are trait that enhances an organism's ability to survive and reproduce in its environment.

5 0

2 years ago

Scientific Method

Leona [35]

Answer:

Problem, Variables, Hypothesis, Research, Procedure, Data, Conclusion.

Explanation:

First, you have to know what the problem that you're talking about is. Then, you have to know the independent, dependent, and controlled variables are in order to make a hypothesis. Then do research about the topic. After that, you make the procedure your experiment, if that's what your doing. Then after the experiment, you find the data. Using that data, you make a conclusion.

4 0

3 years ago

A certain reaction has an activation energy of 66.41 kJ/mol. At what Kelvin temperature will the reaction proceed 3.00 times fas

swat32

Answer : The temperature will be, 392.462 K

Explanation :

According to the Arrhenius equation,

$K=A\times e^{\frac{-Ea}{RT}}$

or,

$\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$K_1$ = rate constant at $T_1$ = $K_1$

$K_2$ = rate constant at $T_2$ = $3K_1$

$Ea$ = activation energy for the reaction = 66.41 kJ/mole = 66410 J/mole

R = gas constant = 8.314 J/mole.K

$T_1$ = initial temperature = 293 K

$T_2$ = final temperature = ?

Now put all the given values in this formula, we get:

$\log (\frac{3K_1}{K_1})=\frac{66410J/mole}{2.303\times 8.314J/mole.K}[\frac{1}{293K}-\frac{1}{T_2}]$

$T_2=392.462K$

Therefore, the temperature will be, 392.462 K

8 0

3 years ago

Element “yellowium” has three naturally occurring isotopes. Below are the masses and relative abundance of each isotope. Find th

katrin [286]

To find average atomic mass, multiply each isotope's atomic mass with its relative abundance and add it all up.

15.012*0.1423 + 16.988*0.3348 + 19.177*0.5229 = 17.851 (5 s.f.)

3 0

3 years ago