Answer:-A. It is less than 890 kJ/mol because the amount of energy required to break bonds is less than the amount of energy released in forming bonds.
Explanation: Endothermic reactions are defined as the reactions in which energy of the product is greater than the energy of the reactants. The total energy is absorbed in the form of heat and 
for the reaction comes out to be positive.
Exothermic reactions are defined as the reactions in which energy of the product is lesser than the energy of the reactants. The total energy is released in the form of heat and for the reaction comes out to be negative.
In the formation of new bonds more energy is released than is required to break the existing bonds, heat is released.
In the formation of bonds less energy is released than is required to break the existing bonds, heat is absorbed.
Answer:
What type of soil filters water best?
Explanation:
dependent variable - the cleanliness of the water after it is filtered
independent variable - soil
control variable - water
(Asking with a <em>please </em>wouldn't hurt -_-)
Answer:
Explanation:autotroph and photosynthesis
sorry if I am wrong I am dumb. :( :(
I found it on google.
God bless, stay safe, and good luck! :) :)
Answer:
The answer is: +7
Explanation:
Oxidation state or oxidation number of an element is the hypothetical charge on an element that forms completely ionic bonds. The oxidation number represents the number of electrons lost or gained by that element.
Perchlorate ion is a molecule with a chemical formula: ClO₄⁻
The oxidation state of oxygen in ClO₄⁻ = -2,
the total charge on the ClO₄⁻ molecule = -1,
let the oxidation state of chlorine be x
<u><em>As the sum of oxidation states of all elements in a molecule is equal to the total charge on the molecule.</em></u>
⇒ oxidation state of chlorine + oxidation state of oxygen × 4 = total charge on the molecule
⇒ x + (-2) × 4 = -1
⇒ x + (-8) = -1
⇒ x = -1 + 8 = +7
⇒<u> </u><u>x = +7</u>
<u>Therefore, the oxidation state of chlorine in the perchlorate ion (ClO₄⁻): x = +7</u>
