Answer : The energy of the photon emitted is, -12.1 eV
Explanation :
First we have to calculate the 
orbit of hydrogen atom.
Formula used :
where,
= energy of 
orbit
n = number of orbit
Z = atomic number of hydrogen atom = 1
Energy of n = 1 in an hydrogen atom:
Energy of n = 2 in an hydrogen atom:
Energy change transition from n = 1 to n = 3 occurs.
Let energy change be E.
The negative sign indicates that energy of the photon emitted.
Thus, the energy of the photon emitted is, -12.1 eV
<em>Phosphoric acid is an acid used in fertilizers and soaps.</em>
<em> Hope this helps:)</em>
Answer:
See explanation and image attached
Explanation:
The reaction of bromine molecule with an alkene passes through a bridged intermediate known as the brominium ion.
It is a cyclic intermediate that contains a positively charged bromine ion as i have shown in the image attached.
The brominium ion is first formed during the bromininaton of alkenes.
