The answer to this is The current atomic model.
Answer:
I’ll give you two possible conditions:
(1) An acid is present in an aqueous solution. The acid will donate a proton to the water to form hydronium. (That’s not really what happens, but that’s how we usually think of it.)
(2) The autoionization of water: in a pure water solution (or not a pure solution, doesn’t matter), one water molecule donates a proton to another water molecule, forming equal numbers of hydronium and hydroxide ions.
Hi there!
We can use the following conversions to solve:
Total mass --> amount of mols --> amount of atoms (Avogadro's number)
Begin by calculating the amount of boron trifluoride in 3.61 grams:
3.61 g * (1 mol BF₃ / 67.8 g) ≈ 0.0532 mol BF₃
Use avogadro's number to convert:
0.0532 mol * 6.02× 10²³atoms / 1 mol = 3.203 × 10²² atoms
Answer:
The molarity of the solution is 0,99M
Explanation:
We calculate the weight of 1 mol of NaCl from the atomic weights of each element of the periodic table. Then, we calculate the molarity, which is a concentration measure that indicates the moles of solute (in this case NaCl) in 1000ml of solution (1 liter)
Weight 1 mol NaCl= Weight Na + Weight Cl= 23 g + 35, 5 g= 58, 5 g
58, 5 g-----1 mol NaCl
145 g ---------x= (145 g x 1 mol NaCl)/58, 5 g= 2,48 mol NaCl
2,5 L solution------ 2, 48 mol NaCl
1 L solution------x= (1 L solutionx 2, 48 mol NaCl)/2,5L solution
x=0,99 mol NaCl---> The solution is 0,99 molar (0,99 M)
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Answer:
There are 1.260 moles for every 300.0 grams of Uranium
Explanation:
