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Bumek [7]
3 years ago
9

Why don't the chocolate chips melt when making cookies

Chemistry
2 answers:
nikitadnepr [17]3 years ago
8 0
You'll see that the chocolate chips<span> are definitely </span>melted<span>. In fact, they won't re-solidify completely for some time afterward. Part of the reason the </span>chocolate chips<span> retain their shape when </span>melted<span> is that they are partially insulated from the heat of the oven by the cookie dough.
        Anna</span>
Ivenika [448]3 years ago
4 0
They do melt, just retain their shape.
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where 1s, 2s, and 2p are the occupied subshells, and the superscript "2" is the number of electrons in each of these subshells.
SOVA2 [1]

Answer: 1s^22s^22p^63s^23p^64s^2

Explanation:

Electronic configuration represents the total number of electrons that a neutral element contains. We add all the superscripts to know the number of electrons in an atom.

The electrons are filled according to Afbau's rule in order of increasing energies where orbital with higher value of (n+l) has higher energy as compared to orbital having lower (n+l) value. Thus the electronic configuration for calcium with atomic number of 20 and hence containing 20 electrons is :

Ca:20:1s^22s^22p^63s^23p^64s^2

8 0
3 years ago
If you place 2 moles of NaCL in a beaker and then add enough water to have a final volume of 0.5 liters, what is the molarity of
julia-pushkina [17]

Answer:

The molarity of the solution is 4M

Explanation:

Molarity is defined as the amount of moles of solute present in one liter of solution. So the molarity of any solution can be found by dividing the moles of solute between the volume in liters of the solution.

For this case we have:

M=\frac{2\:moles\:NaCl}{0.5\:L\:solution} =4M

3 0
3 years ago
Are the strengths of the interactions between the particles in the solute and between the particles in the solvent before the so
Colt1911 [192]

Answer:

Less than

Explanation:

The process of dissolution occurs as a kind of "tug of war". On one side are the solute-solute and solvent-solvent interaction forces, while on the other side are the solute-solvent forces.

Only when the solute-solvent forces are strong enough to overcome the pre-mixing forces do they overcome the "tug of war", and thus dissolution occurs.

Thus, it is concluded that the interaction forces between solute particles and solvent particles before they are combined are less than the interaction forces after dissolution.

5 0
3 years ago
Iridium is a component of cosmic dust that rains down upon the earth at a constant rate. Why did Luis Alvarez suggest measuring
weqwewe [10]

Answer:

In order to determine the rate at which the sediment layers were deposited

Explanation:

Iridium is an important element that belongs to the Platinum group and they are dominantly present in the asteroids and comets. They are the key evidence that suggests the occurrence of an asteroidal impact or a mass extinction event that has taken place in the geological past.

The presence of Iridium mixed with the clay sediments in the boundary between the Cretaceous and Tertiary (K-T boundary) suggested the mass extinction event that wiped out numerous life forms from the earth.

The famous scientist Dr. Luis Walter Alvarez suggested measuring the concentration of Iridium in this K-T boundary in order to determine the rate at which these sediment layers were deposited. They were able to determine that these Iridium elements were present due to the asteroid impact on earth, that wiped out the dinosaurs from the earth. They also considered that this element can be produced from the eruptions of volcanoes.

6 0
3 years ago
Read 2 more answers
What is the final concentration of the solution produced when 225.5 mL of 0.09988-M solution of Na2CO3 is allowed to evaporate u
ikadub [295]

Explanation:

The given data is as follows.

       V_{1} = 225.5 mL,             V_{2} = 45.00 mL

       M_{1} = 0.09988 M,          M_{2} = ?

Therefore, formula to calculate final concentration will be as follows.

                  M_{1}V_{1} = M_{2}V_{2}

Putting the given values into the above formula as follows.

            M_{1}V_{1} = M_{2}V_{2}

   0.09988 M \times 225.5 mL = M_{2} \times 45.0 mL

                    M_{2} = 0.5 M

Thus, we can conclude that the final concentration of the given solution is 0.5 M.

4 0
3 years ago
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