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Shalnov [3]
3 years ago
5

What is the mass of 6.3 moles of Sulfur

Chemistry
2 answers:
Sidana [21]3 years ago
7 0

Answer:

201.6 grams is the mass of 6.3 moles of sulfur.

Explanation:

Moles(n) =\frac{\text{Mass of the compound}(m)}{\text{molar mass of the compound}(M)}

Moles of sulfur ,n= 6.3 moles

Atomic mass of sulfur = M = 32 g/mol

Mass of the sulfur = m = ?

m=M\times n

=6.3 mol\times 32 g/mol=201.6 g

201.6 grams is the mass of 6.3 moles of sulfur.

bixtya [17]3 years ago
6 0
The molar mass of sulfur is 32 g/mol.
The mass of 6.3 moles of Sulfur is 32×6.3=201.6 grams

<span>♡♡Hope I helped!!! :)♡♡
</span>
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How many moles of potassium hydroxide are needed to completely react with 2.94 moles of aluminum sulfate
ArbitrLikvidat [17]

Answer:- Third choice is correct, 17.6 moles


Solution:- The given balanced equation is:


Al_2(SO_4)_3+6KOH\rightarrow 2Al(OH)_3+3K_2SO_4


We are asked to calculate the moles of potassium hydroxide needed to completely react with 2.94 moles of aluminium sulfate.


From the balanced equation, there is 1:6 mol ratio between aluminium sulfate and potassium hydroxide.


It is a simple mole to mole conversion problem. We solve it using dimensional set up as:


2.94molAl_2(SO_4)_3(\frac{6molKOH}{1molAl_2(SO_4)_3})


= 17.6 mol KOH


So, Third choice is correct, 17.6 moles of potassium hydroxide are required to react with 2.94 moles of aluminium sulfate.



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