Magnetism and gravity.
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Answer:
The new electric field strength of this charge is half of the strength of the other charge.
Explanation:
The electric force acting on the charge particle is given by :
F = q E
Where
q is the charged particle
E is the electric field
If the magnitude of a charge is twice as much as another charge, q' = 2q, but the force experienced is the same, then the new electric field is given by :
So, the new electric field strength of this charge is half of the strength of the other charge. Hence, this is the required solution.
Answer:
Explanation:
Given:
- mass of the object,
- elastic constant of the connected spring,
- coefficient of static friction between the object and the surface,
(a)
Let x be the maximum distance of stretch without moving the mass.
<em>The spring can be stretched up to the limiting frictional force 'f' till the body is stationary.</em>
where:
N = m.g = the normal reaction force acting on the body under steady state.
(b)
Now, according to the question:
- Amplitude of oscillation,
- coefficient of kinetic friction between the object and the surface,
Let d be the total distance the object travels before stopping.
<em>Now, the energy stored in the spring due to vibration of amplitude:</em>
<u><em>This energy will be equal to the work done by the kinetic friction to stop it.</em></u>
<em>is the total distance does it travel before stopping.</em>
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