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3 years ago

Please help asap!

Physics

1 answer:

Ivahew [28]3 years ago

8 0

A. Heterogeneous mixture does NOT look the SAME throughout different particles can be seen and physically separated out

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svetoff [14.1K]

Answer:

9.5 seconds

Explanation:

You need to make the ending speed into meters per sec.

So it would be 120km/h = 33.33m/s

If the acceleration rate is 3.5m/s, then the final answer would equal to 9.5 seconds

Also btw rounding it up is a good idea too so 10 seconds if you round

8 0

3 years ago

A man tries to push a 200 kg Car that moves at a acceleration 0.50 m/s2. The man is able to displace the car 10 m. How much work

yawa3891 [41]

The work done by the man pushing the car over the given distance is 1000J.

Given the data in the question;

Mass of car; $m = 200kg$

Acceleration of the car; $a = 0.5m/s^2$

Distance covered by the car; $d = 10m$

Work done; $W = \ ?$

Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;

$Work\ done = f * d$

Where f is force applied and d is distance travelled.

To determine the work done by the man, we first solve for the force applied F.

From Newton's Second Law; $Force \ F = m * a$

We substitute our given values into the expression

$F = m * a \\\\F = 200kg * 0.5m/s^2\\\\F = 100kg.m/s^2$

Next we substitute our values into the expression of work done above.

$Work \ done = f * d\\\\Work \ done = 100kg.m/s^2 * 10m\\\\Work \ done = 1000kgm^2/s^2\\\\Work \ done = 1000J$

Therefore, the work done by the man pushing the car over the given distance is 1000J.

Learn more about work done: brainly.com/question/26115962

7 0

2 years ago

Ice skaters often end their performances with spin turns, where they spin very fast about their center of mass with their arms f

vampirchik [111]

Answer:

$\large \boxed{\text{30 rev/s}}$

Explanation:

This question is based on the Law of Conservation of Angular Momentum.

Angular momentum (L) equals the moment of inertia (I) times the angular speed (ω).

L = Iω

If momentum is conserved,

I₁ω₁ = I₂ω₂

Data:

I₁ = 3.5 kg·m²s⁻¹

ω₁ = 6.0 rev·s⁻¹

I₂ = 0.70 kg·m²s⁻¹

Calculation:

$\begin{array}{rcl}I_{1}\omega_{1} &= &I_{2}\omega_{2}\\\text{3.5 kg$\cdot$m$^{2}$}\times \text{6.0 rev/s} &= &\text{0.70 kg$\cdot$m$^{2}$}\times\omega_{2}\\\text{21 rev/s} &= &0.70\omega_{2}\\\omega_{2} & = & \dfrac{\text{21 rev/s}}{0.70}\\\\&=&\textbf{30 rev/s}\\\end{array}\\\text{The skater's final rotational speed is $\large \boxed{\textbf{30 rev/s}}$}$

8 0

4 years ago

What is the maximum frequency of visible light in hertz?

Nataliya [291]

All frequencies of light in hertz are in between
$Red = 4 * 10 ^{14} Hz$ and
$Violet = 8 * 10 ^{14} Hz$

Light with a lower frequency than 4 * 10^14 Hz, are called infrared and can't be seen by human eye. Light with a higher frequency than 8 * 10^14 Hz, are called ultraviolet and can't bee seen by human eye.

Therefore, the maximum frequency of visible light in Hz, is 8 * 10^14 Hz

3 0

4 years ago

Classify each of the following as a physical or chemical property of

notka56 [123]

A) physical.
b) chemical
c) physical.
d) physical.
e) physical.

7 0

3 years ago