Answer:
Given that
u = 13 m/s
h= 23 m
a) horizontally
We know that acceleration due top gravity is in vertical direction.
v²=u'²+ 2 g h ( u'= 0 )
v² = 2 x 9.81 x 23
v= 21.24 m/s ( vertical direction)
In the horizontal direction
u = 13 m/s
The resultant velocity
V²=v²+u²
V²=21.24²+13²
V= 24.91 m/s
(b) vertically straight up
u= 13 m/s
v²=u²+ 2 g h
v²=13²+ 2 x 9.81 x 23
v= 24.91 m./s
c)vertically straight down.
u= 13 m/s
v²=u²+ 2 g h
v²=13²+ 2 x 9.81 x 23
v= 24.91 m./s
Answer: a? i would need more information
In an Ecosystem, Energy moves from Lower trophic level to higher trophic levels. Example:
Plants ---> rabbit ---> lion
Hope this helps!
Answer:
7.75m/s or 
Explanation:
m = 1.5kg
u= 10m/s
s = 2m
a = 
v = ?
acceleration due to gravity is negative when an object is going up because the force of gravity reduces the speed of the object
using the formula ;
since the object is moving upwards (negative acceleration)
= 100 - 2(10)(2)
100 - 40
= 60
v = 
= 7.75m/s
Answer:
(a) burnout speed at apogee in the external tank disposal orbit=7.82 km/sec
(b) ΔV required for the OMS-1 =0.066 km/sec
(c) ΔV required for the OMS-2 =0.045 km/sec
(d) This part of the question is explained in detailed way in the attached file.
Explanation:
Detailed explanation of all the parts of the question are given in attached files.