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Vinvika [58]
4 years ago
8

Calculate the work performed by an ideal Carnot engine as a cold brick warms from 150 K to the temperature of the environment, w

hich is 300 K. (Use 300 K as the temperature of the hot reservoir of the engine). The heat capacity of the brick is C = 1 kJ/K.
Physics
1 answer:
olga nikolaevna [1]4 years ago
5 0

To solve this problem, apply the concepts related to the calculation of the work performed according to the temperature change (in an ideal Carnot cycle), for which you have to:

W = \int\limit_{T_c}^{T_H} C (1-\frac{T_H}{T})

Where,

C = Heat capacity of the Brick

T_C= Cold Temperature

T_H = Hot Temperature

Integrating,

W = C (T_H-T_C)- T_H C ln (\frac{T_H}{T_C})

Our values are given as

T_H= 300K

T_C = 150K

Replacing,

W = (1) (300-150)-300(1)ln(2)

W = 150-300ln2

W = -57.94kJ \approx 58kJ

Therefore the work perfomed by this ideal carnot engine is 58kJ

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Answer:

heat required in pan B is more than pan A

Explanation:

Heat required to raise the temperature of the substance is given by the formula

Q = ms\Delta T

now we know that both pan contains same volume of water while the mass of pan is different

So here heat required to raise the temperature of water in Pan A is given as

Q_1 = (m_w s_w + m_ps_p)\delta T

Q_1 = (0.5(4186) + 0.750(s))\Delta T

Now similarly for other pan we have

Q_2 = (m_w s_w + m_ps_p)\delta T

Q_2 = (0.5(4186) + 1.50(s))\Delta T

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4 years ago
A 10 N force and a 15 N force are acting from a single point in opposite directions. What additional force must be added to prod
AleksAgata [21]

Answer:

5 N acting in the same direction as the 10 N force

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7 0
3 years ago
A box of unknown mass is sliding with an initial speed vi = 4.70 m/s across a horizontal frictionless warehouse floor when it en
malfutka [58]

Here Change in Kinetic Energy = Work Done by Friction

Therefore, substituting the given values to the equation, we get

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Therefore

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8 0
3 years ago
The energy diagram shows the changes in energy during a chemical reaction.
yanalaym [24]

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D

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You walk 20 m north then 30 m west for a total timer four minutes what is the magnitude of your average velocity in (m/s)
Shalnov [3]

Answer:

The average velocity is 0.15 m/s

Explanation:

Use the definition of average velocity as the distance traveled divided the time it took.

Since the movement was on the plane from the origin (0, 0) to the point (-30, 20) corresponding to 30 m west and 20 m north, we calculate the distance using the distance between two points on the plane:

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Then the magnitude of the average velocity can be estimated via the quotient between distance divided time, but since the units required are meters per second, we first convert the four minute time into seconds: 4 * 60 = 240 seconds.

Then the average velocity becomes:

v_{ave}=\frac{distance}{time} =\frac{36.06}{240} =0.15\,\,m/s

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3 years ago
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