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4 years ago

What is Bernoulli's principle???

1 answer:

maks197457 [2]4 years ago

7 0

The Bernoulli's principle is the principle in hydrodynamics that an increase in the velocity of a stream of fluid results in a decrease in pressure.

You might be interested in

A simple circuit consists of a 100.-ohm resistor

liberstina [14]

If you want to make the total equivalent resistance as small as possible,
then you should connect the new resistor in parallel with the original one.

When resistors are in parallel, then no matter how many of them there are
or what their individual values are, the total equivalent resistance is always
less than the smallest individual one.

For resistors in parallel . . .

 (1 / total resistance) = (1/R₁) + (1/R₂) + (1/R₃) + . . . however many there are.

When there are only two resistors in parallel, you can take that formula, stretch it,
massage it, exercise it, manipulate it, and you find that

 Total equivalent resistance = (product of the resistors) / (sum of the resistors) .

With 100 ohms and 25 ohms in parallel,

 Total equivalent resistance = (100 x 25) / (100 + 25) = 2,500/125 = 20 ohms.

4 0

4 years ago

An ion source is producing 6Li ions, which have charge +e and mass 9.99 × 10-27 kg. The ions are accelerated by a potential diff

Mkey [24]

Answer:

$5.38\cdot 10^5 V/m$

Explanation:

At first, the 6Li ions are accelerated by the potential difference, so their gain in kinetic energy is equal to the change in electric potential energy; so we can write:

$q\Delta V=\frac{1}{2}mv^2$

where

$q=+e=+1.6\cdot 10^{-19}C$ is the charge of one 6Li ion

$\Delta V=9.2 kV=9200 V$ is the potential difference through which they are accelerated

$m=9.99\cdot 10^{-27}kg$ is the mass of each ion

v is the final speed reached by the ions

Solving for v, we find:

$v=\sqrt{\frac{2q\Delta V}{m}}=\sqrt{\frac{2(1.6\cdot 10^{-19})(9200)}{9.99\cdot 10^{-27}}}=5.43\cdot 10^5 m/s$

After that, the ions pass into a region with a uniform magnetic field of strength

$B=0.99 T$

The magnetic field exerts a force perpendicular to the direction of motion of the ions, and this force is given by

$F=qvB$

In order to make the ions passing through undeflected, there should be an electric force balancing this magnetic force. The electric force is given by

$F=qE$

where E is the strength of the electric field.

Since the two forces must be balanced,

$qE=qvB$

From which we get

$E=vB$

So the strength of the electric field must be

$E=(5.43\cdot 10^5)(0.99)=5.38\cdot 10^5 V/m$

4 0

3 years ago

a 3.0 kg mass moving to the right at 1.4 m/s collides in a perfectly inelastic collision with a 2.0 kg mass initially at rest. w

Sedbober [7]

The velocity of the combined mass after the collision is 0.84 ms-1.

Explanation:

According to law of conservation of momentum, the change in momentum before collision will be equal to the change in momentum of the objects after collision in isolated system.

But as it is perfectly inelastic collision in the present case, the final momentum will be based on the product of total mass of both the object with the velocity with which the collision occurred. This form is attained from the law of conservation of momentum as shown below:

So as law of conservation of momentum,

$M_{1} U_{1}+M_{2} U_{2}=M_{1} V_{1}+M_{2} V_{2}$

Here $M_{1}$ = 3 kg and $M_{2}$ = 2 kg are the masses of objects 1 and 2, $U_{1}$ = 1.4 m/s and $U_{2}$ = 0 are the initial velocities of object 1 and object 2, $V_{1}$ and $V_{2}$ are the final velocities of the objects.

So after collision, object 1 get sticked to object 2 and move together with equal velocity $V_{1}$ = $V_{2}$ = $V_{f}$ . Thus the above equation will become,

$M_{1} U_{1}+M_{2} U_{2}=\left(M_{1}+M_{2}\right) V_{f}$

So the final velocity is

$V_{f}=\frac{M_{1} U_{1}+M_{2} U_{2}}{\left(M_{1}+M_{2}\right)}$

Thus,

$V_{f}=\frac{(3 \times 1.4+2 \times 0)}{(3+2)}=\frac{4.2}{5}$ = 0.84 ms-1.

8 0

4 years ago

John rode 3,150 m at an average speed of 350 m/min. If he

Vikentia [17]

Answer:

mabye 8

Explanation:

6 0

3 years ago

What do you think would happen to the force if the distance is cut in half and each of the masses is also cut in half

Rashid [163]

The formula for the force of gravity has ( M₁ · M₂ / D² ) in it.

After the changes, the new force will have ( 0.5M₁ · 0.5M₂ / (0.5D)² ) .

We can separate the new numbers from the original force, like this:

( 0.5M₁ · 0.5M₂ / (0.5D)² )

= ( 0.5 · 0.5 / (0.5)² ) times ( M₁ · M₂ / D² )

The first factor boils down to ' 1 '. So, those changes would
leave the strength of the force unchanged.

That's what I think.

4 0

3 years ago