Answer:
Density, 
Explanation:
Given that,
Mass of a flask is 450 g
Volume of benzene added to the flask is 145 mL or 145 cm³
The weight of the flask and benzene is found to be 754 g.
We need to find the density of the benzene.
Weight of benzene added = total weight of flask and benzene-mass of flask
m = 754 g - 450 g
m = 304 g
Density = mass/volume
So,
So, the density of the benzene is 
.
Answer:Percent error= 90.9%
Explanation:
Percent error or percentage error is defined as the percentage of the difference between a measured value usually from an experiment and an exact value in comparison to the exact number.
its formula is thus
Percent error = experimental value - exact or actual value /exact value x 100
=(18.9 - 9.9 /9.9 ) x 100= 9/9.9) x 100
0.909 x 100 = 90.90 = 90.9%
50.0 mL of 0.500 M HCN and 25.0 mL of 0.500 M sodium hydroxide combination can be used to make a buffer with a pH of 4.2. The KK
an of benzoic acid, C6H5COOH, is 6.5×10-5 and the an of hydrocyanic acid, HCN, is 4.9×10-10.
Benzoic acid
A white (or colourless) solid with the chemical formula C6H5CO2H, benzoic acid is pronounced: "bnzo.k." The simplest aromatic carboxylic acid is this one. The term comes from gum benzoin, which was the substance's exclusive source for a very long period. Many plants naturally contain benzoic acid, which is used as an intermediary in the formation of numerous secondary metabolites[9]. Benzoic acid salts are employed as food preservatives. An essential starting point for the industrial synthesis of many other chemical compounds is benzoic acid. The term "benzoates" refers to the salts and esters of benzoic acid.
To learn more about benzoic acid refer here:
brainly.com/question/24052816
#SPJ 4
Meso−2,3−butanediol is the product of the top reaction
<span>Charles law states that volume of a gas is directly proportional to temperature at constant pressure for a fixed amount of gas. the pressure at given conditions is 1.00 atm and the standard pressure at STP conditions too is 1.00 atm therefore pressure remains constant.
V1/T1 = V2/T2
the parameters for the first instance are on the left side and parameters at STP are on the right side of the equation.
T1 - temperature in kelvin - 273 + 30.0 </span>°C <span>= 303 K
T2 - standard temperature - 273 K
V1 - volume - 50.0 L
substituting the values in the equation
50.0 L / 303 K = V / 273 K V = 45.0 L
answer is 2) 45.0 L </span>
