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Reptile [31]
1 year ago
12

Vinegar contains carbon, hydrogen, and oxygen with percent masses of 40.01% C, 6.70% H, and 53.29% O, respectively. Determine th

e empirical and molecular formulas of the compound. The molar mass of vinegar is about 60 g/mol. HOW DO WE GET THERE
Chemistry
1 answer:
kobusy [5.1K]1 year ago
3 0

The empirical formula is = C2H4O2

Molecular formula=C2H4O2

<h3>Calculation of Molecular formula and empirical formula:-</h3>

Vinegar has three elements:

oxygen = 53.29%,

hydrogen = 6.70%,

and carbon = 40.01%.

We can create an equation for the total mass of vinegar with 'a' carbon atom,' b' hydrogen atom, and 'c' oxygen atoms using the molar masses of C, H, and O.

12*a + 1*b + 16*c = 60

We also know that C makes up 24 g/mol, or 40.01 percent, of the overall mass of 60 g/mol.

The formula contains two C atoms because each C atom has a molecular mass of 12 g/mol. You may determine that the formula contains 4 H and 2 O atoms by using the same reasoning for H and O.

The empirical formula is = C2H4O2

Molecular formula= (C2H4O2)n

(4 x 12 + 1 x 4 + 16 x 2)n = 60

(84)n = 60

n=60/84

n=0.71=1

Molecular formula=C2H4O2

Learn more about Molecular and empirical formulas here:-

brainly.com/question/9207476

#SPJ4

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julsineya [31]

Answer:

The mass of 10 cm³of a 0.4 g/dm³ solution of sodium carbonate is 0.004 grams

Explanation:

The question is with regards to density calculations

The density of the given sodium carbonate solution, ρ = 0.4 g/dm³

The volume of the given solution of sodium carbonate, V = 10 cm³ = 0.01 dm³

Density \ of \ an \ object, \rho  = \dfrac{The \ mass \ of \ the \ object, \ m }{\ The \ volume \ of \ the \ object, \ V }

\rho = \dfrac{m}{V}

Therefore, we have;

The \ Density \ of \ the \ sodium \ carbonate, \ \rho  = 0.4 \ g/dm^3 =  \dfrac{m }{ 0.01 \ dm^3 }

The mass, "m", of the sodium carbonate in  = ρ×V = 0.4 g/dm³ × 0.01 dm³ = 0.004 g

The mass of 10 cm³ (10 cm³ = 0.01 dm³) of a 0.4 g/dm³ solution of sodium carbonate, m = 0.004 g.

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