Question

Vinegar contains carbon, hydrogen, and oxygen with percent masses of 40.01% C, 6.70% H, and 53.29% O, respectively. Determine the empirical and molecular formulas of the compound. The molar mass of vinegar is about 60 g/mol. HOW DO WE GET THERE

Answer 1

The empirical formula is = C2H4O2

Molecular formula=C2H4O2

Calculation of Molecular formula and empirical formula:-

Vinegar has three elements:

oxygen = 53.29%,

hydrogen = 6.70%,

and carbon = 40.01%.

We can create an equation for the total mass of vinegar with 'a' carbon atom,' b' hydrogen atom, and 'c' oxygen atoms using the molar masses of C, H, and O.

12*a + 1*b + 16*c = 60

We also know that C makes up 24 g/mol, or 40.01 percent, of the overall mass of 60 g/mol.

The formula contains two C atoms because each C atom has a molecular mass of 12 g/mol. You may determine that the formula contains 4 H and 2 O atoms by using the same reasoning for H and O.

The empirical formula is = C2H4O2

Molecular formula= (C2H4O2)n

(4 x 12 + 1 x 4 + 16 x 2)n = 60

(84)n = 60

n=60/84

n=0.71=1

Molecular formula=C2H4O2

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