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1 year ago

Which best describes the source of radiation heat

Chemistry

1 answer:

yanalaym [24]1 year ago

7 0

The sun sending out electromagnetic waves is best describes the source of radiation heat.

Radiation heat is the form of electromagnetic waves.

Radiation heat, commonly referred to as thermal radiation, is the electromagnetic radiation that defines how photons exchange heat. The technique of heat transfer known as radiant heat does not require a medium to be propagated in.

Two molecules colliding with each other produce kinetic energy, moving objects have kinetic energy. Radiation heat is thermal energy. Sun directly sends thermal radiation through electromagnetic waves.

Hence , The sun sends out electromagnetic waves directly is best describes the source of radiation heat.

For more information about radiation heat refer given link brainly.com/question/14341157.

#SPJ1.

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A 13.30 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 13.00 grams of CO2 and 2

a_sh-v [17]

Answer: The empirical and molecular formula for the given organic compound is $CHO_2$ and $C_2H_2O_4$

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2=13.00g$

Mass of $H_2O=2.662g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 13.00 g of carbon dioxide, $\frac{12}{44}\times 13.00=3.54g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 2.662 g of water, $\frac{2}{18}\times 2.662=0.296g$ of hydrogen will be contained.

Mass of oxygen in the compound = (13.30) - (3.54 + 0.296) = 9.464 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{3.54g}{12g/mole}=0.295moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.296g}{1g/mole}=0.296moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{9.465g}{16g/mole}=0.603moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.295 moles.

For Carbon = $\frac{0.295}{0.295}=1$

For Hydrogen = $\frac{0.296}{0.295}=1$

For Oxygen = $\frac{0.603}{0.295}=2.044\approx 2$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 1 : 1 : 2

Hence, the empirical formula for the given compound is $CHO_2$

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

$n=\frac{\text{Molecular mass}}{\text{Empirical mass}}$

We are given:

Mass of molecular formula = 90.04 g/mol

Mass of empirical formula = 45 g/mol

Putting values in above equation, we get:

$n=\frac{90.04g/mol}{45g/mol}=2$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_{(1\times 2)}H_{(1\times 2)}O_{(2\times 2)}=C_2H_2O_4$

Hence, the empirical and molecular formula for the given organic compound is $CHO_2$ and $C_2H_2O_4$

3 0

3 years ago

The Pauli Exclusion Principle tells us that no two electrons in an atom can have the same four quantum numbers.

Anuta_ua [19.1K]

Answer:

See explanation

Explanation:

We can describe electrons using four sets of quantum numbers;

principal quantum number (n)

orbital quantum number (l)

magnetic quantum number (ml)

spin quantum number (ms)

Since no two electrons in an atom can have the same value for all four quantum numbers according to Pauli exclusion theory, for the orbitals given one possible value for each quantum number is shown below;

For 1s-

n = 1, l= 0, ml = 0, ms= 1/2

For 2s-

n= 2, l =0, ml=0, ms=1/2

For 1s and 2s orbitals, there is only one possible value for ml which is zero.

3 0

2 years ago

PLEASE HELP: To most humans, the chemical PTC tastes very bitter. The ability to taste it is a dominant trait. People who can’t

algol13

A simply because of I'm a pretty good guesser, Hope this helps.

3 0

3 years ago

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stira [4]

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2 years ago

What mass of silicon dioxide contains 9.72 X10e24 molecules of silicon dioxide?

dangina [55]

Answer:

1033.36g

Explanation:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02x10^23 molecules. This means that 1 mole of SO2 also contains 6.02x10^23 molecules.

1 mole SO2 = 32 + (16x2) = 64g.

Now, If 64g of SO2 contains 6.02x10^23 molecules,

Therefore, Xg of SO2 will contain 9.72x10^24 i.e

Xg of SO2 = (64x9.72x10^24)/6.02x10^23

Xg of SO3 = 1033.36g.

Therefore, 1033.36g of SO2 contains 9.72x10^24 molecules

6 0

3 years ago