Answer: Option (c) is the correct answer.
Explanation:
When the child is tossed up into the air then she gains kinetic energy as the child has moved from its initial position.
It is given that mass is 20 kg, velocity is
, and height is 2 m.
Calculate the kinetic energy of child as follows.
kinetic energy = 
= 
= 
= 
Also, when child falls off the ground then she will have gravitational potential energy.
Calculate gravitational potential energy of child as follows.
Potential energy = m × g × h
= 
= 
Answer:
There is a localization of negative charge near the door handle.
Answer:
Explanation:
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D. Transverse wave
Hope it's correct and helps uh.
Answer:
k_2 = 7.815 * 10^-3 s^-1
Explanation:
Given:
- rate constant of reaction k_1 = 7.8 * 10^-3 s^-1 @ T_1 = 25 C
- rate constant of reaction k_2 = ? @ T_2 = 75 C
- The activation energy E_a = 33.6 KJ/mol
- Gas constant R = 8.314472 KJ / mol . K
Find:
- rate of reaction k_2 @ T_2 = 75 C
Solution:
- we will use a combined form of Arrhenius equations that relates rate constants k as function of E_a and temperatures as follows:
k_2 = k_1 * e ^ [(E_a / R) * ( 1 / T_1 - 1 / T_2 )
- Evaluate k_2 = 7.8 * 10^-3* e^[(33.6 / 8.314472)*(1/298 -1/348)
- Hence, k_2 = 7.815 * 10^-3 s^-1