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3 years ago

Using diagram differentiate between solenoid and a toroid

1 answer:

3 0

The Toroid is form when you have wound conductor around circular body. In this case you have magnatic field inside the core but you dont have any poles because circular body dont have ends. This can be used where you want minimum flux leakage and dont need magnatic poles. i.e. toroidal inductor, toroidal transformer.

The Solenoid is forn when you wound conductor around body with limb. In this case magnatic field creates two poles N and S. Solenoids have little bit flux leakage. This used where you want magnatic poles and flux leakage is not an issue. i.e. relay, motors, electromagnates.

1 == toroid

2= solenoid

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Calculate the tension on the rope.<br> A. 57.89 N<br> B. 32.73 N<br> C. 69.84 N<br> D. 12.55 N

Ratling [72]

Hi there!

$\large\boxed{\text{B. 32.73N}}$

To calculate the tension, we must calculate the acceleration of the system.

Begin with a summation of forces:

∑F = -M₁gsinФ + T - T + M₂g

Simplify and solve for acceleration: (Tensions cancel out)

$a = \frac{-M_1gsin\theta + T - T + M_2g}{M_1+M_2}$

Plug in values. Let g = 10 m/s²

$a = \frac{-3(10)(sin30)+8(10)}{3+8} = 5.91 m/s^{2}$

Now, to find tension, let's sum up the forces acting on ONE block. For simplicity, we can look at the hanging block:

∑F = -T + W

ma = -T + W

Rearrange to solve for T:

T = W - ma

We know the acceleration, so plug in the values:

T = (8)(10) - (8)(5.91) = 32.73 N

3 0

3 years ago

The mohorovicic discontinuity marks the change in rock density between the core and the mantle. mantle and crust. asthenosphere

lions [1.4K]

The transition zone between the crust and mantle is called as mohorovicic discontinuity.

The mohorovicic discontinuity was discovered by Andrija Mohorovicic in the year of 1909. The Moho lies at the depth of 35km beneath the continents and 8km beneath the oceanic crust. The Moho separates both the continental crust and the oceanic crust from underlying mantle. The Moho lies almost entirely within the lithosphere, only beneath the Mid Oceanic Ridge does it define lithosphere and asthenosphere boundary. Immediate above the Moho velocity of the P wave is 6km/sec and just below the Moho it becomes 8km/sec. Moho is characterised by up to 500km thick.

The Mohorovicic Discontinuity marks the lower limit of Earth's crust. It occurs at an average depth of about 8 kilometers beneath the ocean basins and 32 kilometers beneath continental surfaces. Mohorovicic was able to use his discovery to study thickness variations of the crust.

Mohorovicic discontinuity is the layer which is between the earth's crust and mantle. It's density ranges from 3.3 to 3.7.

learn more about mohorovicic discontinuity from here: brainly.com/question/2887207

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3 0

1 year ago

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nydimaria [60]

Answer:

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Explanation:

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2 years ago

A boat moves through the water with two forces acting on it. One is a 2.05 ✕ 103 N forward push by a motor, and the other is a 1

labwork [276]

Answer:

(a) a= 0.139 m/s²

(b) d= 4.45 m

Explanation:

a) We apply Newton's second law:

∑F = m*a Formula (1)

∑F : algebraic sum of the forces in Newton (N)

m : mass (kg)

a : acceleration (m/s²)

Data

F₁= +2.05 * 10³ N : forward push by a motor

F₂= -1.87* 10³ N : resistive force due to the water.

m= 1300 kg

Calculation of the acceleration of the boat

We replace data in the formula (1):

∑F = m*a

F₁+F₂= m*a

$a=\frac{F_{1} +F_{2} }{m}$

$a= \frac{2.05*10^{3} -1.87*10^{3}}{1300}$

a= 0.139 m/s²

b) Kinematics of the boat

Because the boat moves with uniformly accelerated movement we apply the following formulas:

d= v₀t+ (1/2)*a*t² Formula (2)

vf= v₀+at Formula (3)

Where:

d:displacement in meters (m)

t : time interval (s)

v₀: initial speed (m/s)

vf: final speed (m/s)

a: acceleration (m/s² )

Data

v₀ = 0

a= 0.139 m/s²

t = 8 s

Calculation of the distance traveled by the boat in 8 s

We replace data in the formula (2)

d= v₀t+ (1/2)*a*t²

d= 0+ (1/2)*(0.139)*(8)²

d= 4.45 m

c) Calculation of the speed of the boat in 8 s

We replace data in the formula (3):

vf= v₀+at

vf= 0+( 0.139)*(8)

vf= 1.1 m/s

6 0

4 years ago

Three moles of an ideal gas undergo a reversible isothermal compression at 22.0°C. During this compression, 1700 J of work is do

densk [106]

Answer:

change in entropy is - 5.7627 J/K

Explanation:

Given data

temperature = 22.0°C = 22 + 273 = 295 K

work is done = 1700 J

to find out

change in entropy

solution

we know that change in entropy = Q /T ......1

from 1st law of thermodynamic we know

Q =W for change in internal energy = 0

Q = -1700 J

so from equation 1

change in entropy = - 1700 / 295

change in entropy = - 5.7627

so change in entropy is - 5.7627 J/K

5 0

3 years ago