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myrzilka [38]
2 years ago
8

The gravitational constant G was first measured accurately by Henry Cavendish in 1798. He used an exquisitely sensitive balance

to measure the force between two lead spheres whose centers were 0.27 m apart. One of the spheres had a mass of 188 kg, while the mass of the other sphere was 0.93 kg.
What was the ratio of the gravitational force between these spheres to the weight of the lighter sphere?
Physics
1 answer:
belka [17]2 years ago
7 0

The gravitational force between the spheres is

F_{\rm g}=\dfrac{G(188\,\mathrm{kg})(0.93\,\mathrm{kg})}{(0.27\,\mathrm m)^2}\approx1.6\times10^{-7}\,\mathrm N

where <em>G</em> = 6.674 x 10⁻¹¹ N m²/kg².

The weight of the lighter sphere is

F_{\rm w}=(0.93\,\mathrm{kg})g\approx9.1\,\mathrm N

where <em>g</em> = 9.80 m/s².

The ratio between the two forces is then

\dfrac{F_{\rm g}}{F_{\rm w}}\approx1.8\times10^{-8}

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1.0 x 10^9= 1000000000
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At which type of boundary between two tectonic plates is an earthquake or a tsunami most likely to form?
Fofino [41]

Answer:

B. convergent boundary

Explanation:

Convergent boundaries, where ocean plates are subducted at trenches, produce the most tsunamis because they produce the largest earthquakes

7 0
3 years ago
A box slides down a frictionless incline, gaining speed. The work done by the normal force n is _______.
jeka57 [31]

The work done by the normal force n when the box slides down a frictionless incline and gaining speed is zero.

<h3>What is normal force?</h3>

The force of contact is called the normal force. When the two surfaces are in contact with each other, then the normal force acts.

This force is applied by the solid bodies on each other in order to prevent the passing through each other.

A box slides down a frictionless incline, gaining speed. For this box, the value of work done by normal force has to be found out. Let's analyze the given condition.

  • The body is gaining the speed, which means there is a change in kinetic energy.
  • The change in kinetic energy is equal to the work done.
  • The friction force is the product of coefficient of the friction and normal force.
  • The friction force for the given case is zero. Thus, the normal force must be equal to the zero.

Thus, the work done by the normal force n when the box slides down a frictionless incline and gaining speed is zero.

Learn more about the normal force here;

brainly.com/question/10941832

7 0
1 year ago
Read 2 more answers
Newton's third law can be summarized as "every action has an equal and opposite reaction". In this problem, consider the action
scoundrel [369]

Answer:

Action force: Would be the force of your feet against the Earth given by the weight defined as:

W = mg

Where g is a constat who represent the gravity g =9.8 m/s^2 in Earth

Reaction force: Would be the force of the Earth pushing against your feet. And on this case is represented by the normal force defined as:

N = \mu f_f

Where \mu represent the friction coefficient between the ground and the object.

And f_f the friction force.

If we don't have any other forces involved in the y axis we can conclude that:

W=N= mg

And as we can see we have that Action force = Reaction force

So then the third Law of Newton is satisfied.

Explanation:

For this case we have this:

Action force: Would be the force of your feet against the Earth given by the weight defined as:

W = mg

Where g is a constat who represent the gravity g =9.8 m/s^2 in Earth

Reaction force: Would be the force of the Earth pushing against your feet. And on this case is represented by the normal force defined as:

N = \mu f_f

Where \mu represent the friction coefficient between the ground and the object.

And f_f the friction force.

If we don't have any other forces involved in the y axis we can conclude that:

W=N= mg

And as we can see we have that Action force = Reaction force

So then the third Law of Newton is satisfied.

7 0
3 years ago
The density of silver is 10.5 g cm3. a piece of silver with a mass of 61.3 g would ovvupy a volume of ?
natali 33 [55]
The relationship between mass m, volume V and density d is:
d= \frac{m}{V}
The silver has density d=10.5 g/cm^3, and the mass of the piece of silver is m=61.3 g. Therefore we can calculate its volume using the previous formula:
V= \frac{m}{d}= \frac{61.3 g}{10.5 g/cm^3}=5.84 cm^3
7 0
2 years ago
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