Answer:
6.7 m/s
Explanation:
In the vertical direction:
y₀ = 0.63 m
y = 0 m
v₀ᵧ = 0 m/s
aᵧ = -9.81 m/s²
In the horizontal direction:
x₀ = 0 m
x = 2.4 m
aₓ = 0 m/s²
Find: v₀ₓ
First, find the time:
y = y₀ + v₀ᵧ t + ½ aᵧt²
0 = 0.63 + (0) t + ½ (-9.81) t²
t = 0.358
Now, find the velocity:
x = x₀ + v₀ₓ t + ½ aₓt²
2.4 = 0 + v₀ₓ (0.358) + ½ (0) (0.358)²
v₀ₓ = 6.70
Rounded to two significant figures, the cat's velocity when it slides off the table is 6.7 m/s.
Answer:
The acceleration of the plane is -2.14 m/s² ⇒ 2nd answer
Explanation:
<u><em>Acceleration</em></u> is the rate of change of velocity
The unit for acceleration is meters per second square
The rule of the acceleration is: → 
where a is the acceleration, u is the initial velocity, v is the final velocity
and t is the time
An airplane traveling 245 m/s east experiences turbulence so the pilot
slows down to 230 m/s
It takes the pilot 7 seconds to slow down to this speed
We need to find the acceleration of the plane
Lets use the rule above
→ u = 245 m/s , v = 230 m/s , t = 7 seconds
→ 
→ 
→ The acceleration is -2.14 m/s²
<em>The acceleration of the plane is -2.14 m/s²</em>