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saul85 [17]
3 years ago
7

An object moves 20 m east in 30 s and then returns to its starting point taking an additional 50 s. If west is chosen as the pos

itive direction, what is the average speed of the object
Physics
1 answer:
user100 [1]3 years ago
7 0

Answer:

v = 0.5 m/s.

Explanation:

Total distance, d = 20 m + 20 m = 40 m

Total time taken, t = 30 s + 50 s = 80 s

The average speed of an object is the total distance divided by time taken. So,

v=\dfrac{40}{80}\\\\=0.5\ m/s

So, the average speed of the object is 0.5 m/s.

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If the new moon happens on January 15th, what shape will it be on February 6th?
Jobisdone [24]

-- From January 15 to February 6 is a period of 22 days.

-- The period of the full cycle of moon phases is 29.53 days.

-- So those dates represent (22/29.53) = 74.5% of a full cycle of phases.

-- That's almost exactly 3/4 of a full cycle, so on February 6, the moon would be almost exactly at <em>Third Quarter</em>.  That's the <em>left half of a disk </em>(viewed from the northern hemisphere).

3 0
3 years ago
This glass of lemonade is sitting in the hot summer sun. As time passes, in which direction will heat transfer take place?
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Answer:

c

Explanation:

8 0
3 years ago
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A 3-m-high, 7-m-wide rectangular gate is hinged at the top edge and is restrained by a fixed ridge. Determine the hydrostatic fo
Shalnov [3]

Answer:

The Hydrostatic force is   F  =  137.2 kN

The location of pressure center is  Z  = 1.333 \ m  

Explanation:

From the question we are told that

   The height of the gate is  h =  3 \ m

     The weight of the gate is  w =  7 \  m

      The height of the water is  h_w  =  2 \ m

       The density of water is \rho_w  =  1000 \ kg/m^3

Note used h_w for height of water and height of gate immersed by water since both have the same value

The area of the gate immersed in water  is mathematically represented as

         A =  h_w  * w

substituting values

         A =  2*  7

         A =  14  \ m^2

The hydrostatic force is mathematically represented as

          F  =  \rho_w * g * h_f * A

Where

            h_f =h-  h_w

           h_f =3 -2

           h_f = 1\ m  

So  

              F  =  1000 * 9.8 * 1 * 14

            F  =  137.2 kN

The center of pressure is mathematically represented as

        Z  =  h_f + \frac{I_g}{h_f * A}

Where I_g is the moment of inertia of the gate which mathematically represented as

            I_g =  \frac{w * h_w^2}{12}

The h_w is the height of gate immersed in water

            I_g =  \frac{7  * 2^2 }{12}

             I_g = 4.667\ kg  m^2

Thus  

        Z  = 1  + \frac{4.66}{1 * 14}

        Z  = 1.333 \ m

3 0
3 years ago
Agility is the
olga_2 [115]

Answer:

combination of strength and speed

Explanation:

please like and Mark as brainliest

8 0
3 years ago
How far did a frog jump if he travels at a rate of 2.1 m/s for 10 seconds?
Anestetic [448]

Answer:

21 m

Explanation:

The motion of the frog is a uniform motion (constant speed), therefore we can find the distance travelled by using

d=vt

where

d is the distance covered

v is the speed

t is the time

The frog in this problem has a speed of

v = 2.1 m/s

and therefore, after t = 10 s, the distance it covered is

d=(2.1)(10)=21 m

3 0
3 years ago
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