All categories

2 years ago

how many meters would you have traveled after 90 minutes if you're average velocity is 4 kilometers per hour?

Physics

1 answer:

Gekata [30.6K]2 years ago

5 0

Answer:

<h2>6,000 Meters.</h2>

Hope this helps you! :)

You might be interested in

Astronomers estimate that a 2

tia_tia [17]

M)³ / 6 = 4.2e9 m³
so its mass is 
M = 3300kg/m³ * 4.2e9m³ = 1.4e13 kg 
and so its KE at 16 km/s = 16000 m/s is 
KE = ½ * 1.4e13kg * (16000m/s)² = 1.8e21 J

# of bombs N = 1.8e21J / 4.0e16J/bomb = 44 234 bombs
give or take.

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

6 0

2 years ago

I’ll give u BRAINLIEST PLEASE!! HURRY

zalisa [80]

Answer:

Explanation:

6 0

2 years ago

Fifteen identical particles have various speeds: one has a speed of 2.00 m/s, two have speeds of 3.00 m/s, three have speeds 5.0

Tems11 [23]

A. Average speed is weighted mean (1 × 2 + 2 × 3 + 3 × 5 + 4 × 7 + 3 × 9 + 2 × 12.5)/15 = (2 + 6 + 15 + 28 + 27 + 25)/15 = 103/15 = 6.867 b. RMS is square root of 1/15 times sum of squares of speeds Sum of squares is 4 + 9 + 9 + 25 + 25 + 25 + 49 + 49 + 49 + 49 + 81 + 81 + 81 +156.25 + 156.25 = 848.5
c. RMS speed = √(848.5/15) = 7.521
Most likely the speed is the peak in the speed distribution, which is 7.

5 0

2 years ago

A two-dimensional section of the body is known as an

lesya692 [45]

Median plane ..........

7 0

2 years ago

A water balloon launcher uses an elastic band with a spring constant of 115 N/m. To use the launcher, you stretch the band back

Lorico [155]

Here elastic balloon launcher will behave like an ideal spring

so here we have

spring constant k = 115 N/m

mass of balloon = 1.3 kg

Part a)

Stretch in the band is given as

x = 0.8 m

now the force on the balloon is given by

F = k x

now from above

$F = (115) (0.8) = 92 N$

so it will exert 92 N force on it

Part b)

Elastic potential energy is given as

$U = \frac{1}{2}kx^2$

so here we have

$U = \frac{1}{2}(115)(0.8)^2$

$U = 36.8 J$

Part c)

Here in this case we can say that kinetic energy gained by the balloon must be same as the elastic potential energy stored in the rubber because there is no energy loss in this system

So kinetic energy = 36.8 J

Part d)

As we know by the formula of kinetic energy

$K = \frac{1}{2}mv^2$