Answer:
Step-by-step explanation:
Middle point of AB
x(m) = (6+1)/2 = 7/2
y(m) = (7+4)/2 = 11/2
slope of the line that contains AB
(4-7)/(6-1) = -3/5
eqaution of the perpendicular bisector
y-11/2 = 5/3(x-7/2)
y = 5/3x -35/6 + 11/2
y = 5/3x + (-35 + 33)/6
y = 5/3x -1/3
Middle point of AC
x(m) = (1+5)/2 = 3
y(m) = (7+5)/2 = 6
Slope of the line that contains AC
(5-7)/(5-1) = -1/2
equation of the perpendicular bisector
y-6 = 2(x-3)
y = 2x -6 + 6
y = 2x
Point of intersection
y= 5/3x -1/3
y = 2x
2x = 5/3x - 1/3
6x = 5x - 1
x = -1
y = -2
P(-1,-2)
Consider the data set shown below. 42, 43, 46, 47, 47, 48, 49, 50, 51, 53, 55, 55, 59 A graph shows intervals labeled 40 to 43 t
LenKa [72]
Answer:
3 , 4 , 1
Step-by-step explanation:
The interval 44-47 has a frequency of 3
The interval 48-51 has a frequency of 4
The interval 56-59 has a frequency of 1
got it right on edge
Answer:
The correct way to read 43.106 would be forty-three and one hundred 6 hundredths.
Step-by-step explanation:
The only safe conclusion is that point G lies on line FH or that point G lies somewhere between line FH. We cannot conclude that point G is the midpoint of line FH eventhough by virtue of definition of midpoint, the given equation is a proof equation. If G were to be midpoint, segment FG must be equal to segment GH in line FH.
A dekameter is = to 10 meters,
10x3=30
30÷1=30
Glenn can make 30 ribbon key chains.