The amount of force needed to keep a 0.5 kg football moving at a constant speed of 8 m/s

A sample of a diatomic ideal gas has pressure P and volume V. When the gas is warmed, its pressure triples and its volume double

Andreyy89

Answer:

Amount of Energy transferred $=8.5PV$

Explanation:

Given:

Initial volume=V

Initial pressure=P

Final volume=2V

Final pressure=3P

Now w know that the Energy transferred in constant pressure pressure is given by

$E_1=nc_pdT\\\\E_1=n\times\dfrac{7R}{2}dT\\E_1=3.5(nRdT)\\E_1=3.5(V(2P-P))\\E_1=3.5PV$

Now the Energy transferred in constant volume process is given by

$E_2=nc_vdT\\\\E_2=n\times\dfrac{5R}{2}dT\\E_1=2.5(nRdT)\\E_1=2.5(V(3V-V))\\E_1=5PV$

The total Energy transferred is given by

$E_{total}=E_1+E_2\\E{total}=3.5PV+5PV\\=8.5PV$

3 0

3 years ago

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A 4.00kg counterweight is attached to a light cord, which is would around a spool. The spool is a uniform solid cylinder of radi

Sergio [31]

Answer:

Explanation:

Given that,

Mass of counterweight m= 4kg

Radius of spool cylinder

R = 8cm = 0.08m

Mass of spool

M = 2kg

The system about the axle of the pulley is under the torque applied by the cord. At rest, the tension in the cord is balanced by the counterweight T = mg. If we choose the rotation axle towards a certain ~z, we should have:

Then we have,

τ(net) = R~ × T~

τ(net) = R~•i × mg•j

τ(net) = Rmg• k

τ(net) = 0.08 ×4 × 9.81

τ(net) = 3.139 Nm •k

The magnitude of the net torque is 3.139Nm

b. Taking into account rotation of the pulley and translation of the counterweight, the total angular momentum of the system is:

L~ = R~ × m~v + I~ω

L = mRv + MR v

L = (m + M)Rv

L = (4 + 2) × 0.08

L = 0.48 Kg.m

C. τ =dL/dt

mgR = (M + m)R dv/ dt

mgR = (M + m)R • a

a =mg/(m + M)

a =(4 × 9.81)/(4+2)

a = 6.54 m/s

6 0

4 years ago

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In which of the following substances would convection most likely occur?

VikaD [51]

Answer:

Air and ice

Explanation:

convection, process by which heat is transferred by movement of a heated fluid such as air or water.

Everyday Examples of Convection:

radiator - A radiator puts warm air out at the top and draws in cooler air at the bottom.

steaming cup of hot tea - The steam you see when drinking a cup of hot tea indicates that heat is being transferred into the air.

ice melting - Ice melts because heat moves to the ice from the air.

7 0

2 years ago

you will For this problem, you will need to look up physical parameters for objects in space want to keep about 4 significant fi

Tanzania [10]

Answer:

a) r₁ = 3.836 10⁷ m, b) F = - 3,390 10⁸ N , c) R = 120.3 m

Explanation:

a) This is a problem of equilibrium where the force is gravitational, we call F1 the force of the Moon and F2 the force from the earth.

F₁ -F₂ = 0

F₁ = F₂

G m $M_{m}$ / r₁² = G m $M_{e}$ / r₂²

Let's look for the measured distance from a Coordinate System located on the Moon,

r₂ = D - r₁

Where D is the average distance from Terra to the Moon 3.84 10⁸ m

$M_{m}$ / r₁² = $M_{e}$ / (D - r₁)²

(D² - 2 D r₁ + r₁²) = $M_{e}$ / $M_{m}$ r₁²

(1 - $M_{e}$ / $M_{m}$ )r₁² - 2D r₁ + D² = 0

Let's replace and solve the second degree equation

(1 - 5.98 10²⁴ / 7.36 10²²) r₁² - 2 3.84 10⁸ r₁ + (3.84 10⁸)² = 0

-80.25 r₁² - 7.68 10⁸ r₁ + 14.75 10¹⁶ = 0

r₁² + 9.57 10⁶ r₁ - 1.838 10¹⁵ = 0

r₁ = [-9.57 10⁶ ±√ (91.58 10¹² + 7.352 10¹⁵)] / 2

r₁ = [-9.57 10⁶ + - 86.28 10⁶] / 2

The results are:

r₁’= 38.355 10 6 m

r₁ ’’ = -47.915 10 6 m

We take the positive result that a distance between the moon and the Earth, the equalization point is r₁ = 3.836 10⁷ m

b) The force at point R = 2 r₁

R = 2 3.8355 10⁷ = 7.671 10⁷ m

F = F₁ - F₂

F = G m $M_{m}$ / R² - G m $M_{e}$ / (D- R)²

F = G m ( $M_{m}$ / R² - $M_{e}$ / (D-R)²)

F = m 6.67 10⁻¹¹ (7.36 10²² / (7.671 10⁷)² - 5.98 10²⁴ / (3.84 10⁸ - 0.7671 10⁸)²

F = m 6.67 10⁻¹¹ (0.125076 10⁸ - 0.63329 10⁸)

F = m (-3.3897 10⁸) N

The mass m of the rocket must be known, suppose it is worth 1 kg (m = 1 kg)

F = - 3,390 10⁸ N

c) let's use gravitational force from the moon

F = G m $M_{m}$ / R²

R =√ G m $M_{m}$ / F

R = √ (6.67 10⁻¹¹ 1 7.36 10²² / 3.3897 10⁸)

R = √ (1.4482 10⁴)

R = 1.2034 10² m

R = 120.3 m

8 0

3 years ago

A student moves the end of a compressed coiled spring up and down to demonstrate wave

Akimi4 [234]

Given what we know, we can confirm that when the student moves the compressed coiled spring faster but <u>keeps everything else the same</u>, she is effectively increasing the wave frequency of the model.

<h3>What we know about wave frequency.</h3>

Wave frequency measures number of times waves pass through a specific point over an interval of time.
This refers to the speed at which waves are passing, which increases when the student moves the coiled spring faster.
The amplitude of the wave model is given by the coil's length.
The crest and wavelengths are given by the shape and length of the coil respectively.

We can confirm that since the student did not make any changes to the shape of the coil, its compression, or its length, she did not affect the amplitude, crest, or wavelength for the model. Therefore, only the frequency of the wave model increased with this change.

To learn more about Wave frequency visit:

brainly.com/question/14588679?referrer=searchResults

4 0

2 years ago