Answer:
Range, 
Explanation:
The question deals with the projectile motion of a particle mass M with charge Q, having an initial speed V in a direction opposite to that of a uniform electric field.
Since we are dealing with projectile motion in an electric field, the unknown variable here, would be the range, R of the projectile. We note that the electric field opposes the motion of the particle thereby reducing its kinetic energy. The particle stops when it loses all its kinetic energy due to the work done on it in opposing its motion by the electric field. From work-kinetic energy principles, work done on charge by electric field = loss in kinetic energy of mass.
So, [tex]QER = MV²/2{/tex} where R is the distance (range) the mass moves before it stops
Therefore {tex}R = MV²/2QE{/tex}
<span>This is best understood with Newtons Third Law of Motion: for every action there is an equal and opposite reaction. That should allow you to see the answer.</span>
Answer:
Option D. The average speed is 2.5 meters/second, and the average velocity is 0 meters/second.
Explanation:
we know that
To find out the average speed divide the total distance by the total time
Let
d -----> the total distance in meters
t -----> the time in seconds
s ----> the speed in meters per second
Remember that
we have
substitute
<u><em>Find out the average velocity</em></u>
To find out the average velocity divide the displacement) by the time
The displacement is the distance from the start point to the end point regardless of the route
In this problem
The start point is A and the end point is A
so
The displacement is equal to zero
therefore
The average velocity is 0 m/sec
Answer:
A- 20 protons and 20 electrons
Explanation:
Answer:
549.9 ohms, 65.65 watts, the power went up
Explanation: power P = V²/R
v= 190volts , P =62watts
from P =V²/R
62=190²/R
making R the subject
R×62= 190²
62R =36100
R=36100/62
R=586.25 ohms
Resistance of each lamp = 586.26/18 =32.3ohms
a) resistance of the light string now = 17×32.3 = 549.9 ohms
b) P=V²/R
where R=549.9ohms , P=?
P=190²/549.9
P=36100/549.9
P=65.65watts
Power dissipated has increased( went up )
