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tatyana61 [14]
3 years ago
6

Which is a chemical property of soda ash

Chemistry
2 answers:
Jobisdone [24]3 years ago
8 0

Answer:

The answer would be A. It's a highly basic substance.

Katen [24]3 years ago
5 0
It's a highly basic substance. 


Good luck! (:
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Use the chart to answer the following question. I Nuclear energy does not produce dangerous waste products. Nuclear energy is si
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Nuclear energy is significantly cheaper then production of energy from fossil II fuels

Explanation:

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How is gravity an attractive force?
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Gravitational force -an attractive force that exists between all objects with mass; an object with mass attracts another object with mass; the magnitude of the force is directly proportional to the masses of the two objects and inversely proportional to the square of the distance between the two objects.
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If a gas’s [kelvin] temperature doubles and it’s volume then remains the same, then what happens to it’s pressure?
Tamiku [17]

Answer:

The final pressure will double i.e it will be twice the initial pressure

Explanation:

T1 = T

T2 = 2T ( twice the original T)

P1 = P

P2 =?

Since the volume is constant,

P1/ T1 = P2 /T2

P/ T = P2 / 2T

Cross multiply

T x P2 = 2T x P

Divide both side by T

P2 = (2T x P) / T

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Therefore, the final pressure will double i.e it will be twice the initial pressure

5 0
3 years ago
The structure shown is an example of what kind of molecule?
mihalych1998 [28]
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Hydrogen sulfide,H2S, is a very toxic gas with a smell of rotten eggs. using the following: H2S+3/2 O2=SO2+H2O H2+1/2O2=H2O S+O2
Serga [27]

Answer:

ΔH = -20kJ

Explanation:

The enthalpy of formation of a compound is defined as the change of enthalpy during the formation of 1 mole of the substance from its constituent elements. For H₂S(g) the reaction that describes this process is:

H₂(g) + S(g) → H₂S(g)

Using Hess's law, it is possible to sum the enthalpies of several reactions to obtain the change in enthalpy of a particular reaction thus:

<em>(1) </em>H₂S(g) + ³/₂O₂(g) → SO₂(g) + H₂O(g) ΔH = -519 kJ

<em>(2) </em>H₂(g) + ¹/₂O₂(g) → H₂O(g) ΔH = -242 kJ

<em>(3) </em>S(g) + O₂(g) → SO₂(g) ΔH = -297 kJ

The sum of -(1) + (2) + (3) gives:

<em>-(1) </em>SO₂(g) + H₂O(g) → H₂S(g) + ³/₂O₂(g) ΔH = +519 kJ

<em>(2) </em>H₂(g) + ¹/₂O₂(g) → H₂O(g) ΔH = -242 kJ

<em>(3) </em>S(g) + O₂(g) → SO₂(g) ΔH = -297 kJ

<em>-(1) + (2) + (3): </em><em>H₂(g) + S(g) → H₂S(g) </em>

<em>ΔH =</em> +519kJ - 242kJ - 297kJ = <em>-20 kJ</em>

<em />

I hope it helps!

5 0
3 years ago
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