Answer:
geologic features like craters and mountains
Explanation:
Answer:
pCl⁻ = 0.54
Explanation:
First we <u>calculate how many Cl⁻ moles are coming from each substance</u>, using the <em>given volumes and concentrations</em>:
- 0.12 M NaCl * 0.10 L = 0.012 mol NaCl = 0.012 mol Cl⁻
- 0.18 M MgCl₂ * 0.23 L = 0.0414 mol MgCl₂ = (0.0414 * 2) 0.0828 mol Cl⁻
The final volume of the mixture is = 0.10 L + 0.23 L = 0.33 L
Now we <u>calculate [Cl⁻]</u>, using the<em> total number of Cl⁻ moles and the final volume:</em>
- [Cl⁻] = (0.012 mol + 0.0828 mol) / 0.33 L = 0.29 M
Finally we <u>calculate the pCl⁻ of the resulting solution</u>:
Answer:
3 moles
Explanation:
3 moles atoms are needed to react with 50 grams of O2 gas.
Answer:
The most important thing to know is that an α-particle (alpha particle) is a helium nucleus.
Explanation:
It contains 2 protons and 2 neutrons, for a mass number of 4.
During α-decay, an atomic nucleus emits an alpha particle. It transforms (or decays) into an atom with an atomic number 2 less and a mass number 4 less.
Thus, radium-226 decays through α-particle emission to form radon-222 according to the equation:
226
88
Ra
→
222
86
Rn
+
4
2
He
Note that the sum of the subscripts (atomic numbers or charges) is the same on each side of the equation. Also, the sum of the superscripts (masses) is the same on each side of the equation.
EXAMPLE
Write a balanced nuclear equation for the α decay of polonium-208.
Solution
The unbalanced equation is
208
84
Po
→
4
2
He
+
X
The superscript of
X
must be 208 – 4 = 204.
The subscript of
X
must be 84 – 2 = 82.
Element 82 is Pb. So the equation is
208
84
Po
→
4
2
He
+
204
82
Pb
Explanation:hope this is right and helps
41.083 atm is the difference between the ideal pressure (as predicted by the ideal gas law) and the real pressure (as predicted by the van der Waals equation.
Explanation:
Data given for argon gas:
number of moles = 1 mole
volume = 0.5 L
Temperature = 19 degrees or 292.15 K
a= 1.345 (L2⋅atm)/mol2
b= 0.03219L/mol.
R = 0.0821
The real pressure equation given by Van der Waals equation:
P =( RT ÷ Vm-b) - a ÷ Vm^2
Putting the values in the equation:
P = (0.0821 x 292.15) ÷(0.5 - 0.03219) - 1.345÷ (0.5)^2
= 23.98÷0.4678 - 1.345 ÷0 .25
= 51.26 - 5.38
= 45.88 atm is the real pressure.
The pressure from the ideal gas law
PV =nRT
P =( 1 x 0.0821 x 292.15) ÷ 0.5
= 4.797 atm
the difference between the ideal pressure and real pressure is
Pressure by vander waal equation- Pressure by ideal gas law
45.88 - 4.797
= 41.083 atm.is the difference between the two.