Rank the following measurements in order from least to greatest

Solid iron combines with oxygen gas to form solid iron(III) oxide. Which of the following equations best describes this reaction

Alexus [3.1K]

Answer:

B. 4 Fe + 3 0₂---> 2 Fe₂O3

Explanation:

(A) Ir + O₂--> IrO₂ No: Ir is iridium

(B) 4 Fe + 3 0₂---> 2 Fe₂O3 Yes: Fe is iron and O is oxygen, and the equation is balanced.

(C) I+ 0₂ ---> 10₂ No: I is iodine

(D) 3 Ir + 0₂ -> 6 Ir₂03 No: I is iodine

3 0

1 year ago

Hydrogen is a special ,because it can act like two groups,____and_____

LuckyWell [14K]

Answer:

First and seventeenth group.

Explanation:

Hydrogen is a special case as it has only one electron in its outermost orbital.

The hydrogen can lose or can accept electron easily.

Thus it can form positive ion similar to alkali metals and negative ion similar to halogens.

Thus it can fall into two groups

a) I group [Alkali metals]

b) 17th Group [Halogens]

5 0

3 years ago

Select the property that is not a characteristic of an ideal recrystallization solvent.

dybincka [34]

Answer:

(C) The recrystallization solvent should be nonvolatile.

Explanation:

Recrystallization is the separation technique which is used to purify the solid compounds in their crystal or amorphous form.

Some properties follow the recrystallization process as:

The solids are more soluble in hot solvent as compared to the solubility in the cold solvent.

The solvent must have lower boiling point and can be volatile easily.

The solvent should not react with the compound.

The impurities must be soluble in the cool solvent, so that only the pure product crystallizes.

Hence, Answer - C which is not an ideal characteristic.

8 0

3 years ago

Solid aluminum (AI) and oxygen (O_2) gas react to form solid aluminum oxide (Al_2O_3). Suppose you have 7.0 mol of Al and 9.0 mo

Nimfa-mama [501]

Answer:

There will be formed 3.5 moles of Al2O3 ( 356.9 grams)

Explanation:

Step 1: Data given

Numbers of Al = 7.0 mol

Numbers of mol O2 = O2

Molar mass of Al = 26.98 g/mol

Molar mass of O2 = 32 g/mol

Step 2: The balanced equation

4Al(s) + 3O2(g) → 2Al2O3(s)

Step 3: Calculate limiting reactant

For 4 moles Al we need 3 moles O2 to produce 2 moles Al2O3

Al is the limiting reactant, it will be consumed completely (7 moles).

O2 is in excess. There will react 3/4 * 7 = 5.25 moles

There will remain 9-5.25 = 3.75 moles

Step 4: Calculate moles Al2O3

For 4 moles Al we'll have 2moles Al2O3

For 7.0 moles of Al we'll have 3.5 moles of Al2O3 produced

Step 5: Calculate mass of Al2O3

Mass Al2O3 = moles Al2O3 * molar mass Al2O3

Mass Al2O3 = 3.5 moles* 101.96 g/mol

Mass Al2O3 = 356.9 grams

There will be formed 3.5 moles of Al2O3 ( 356.9 grams)

3 0

3 years ago

The standard enthalpy of formation of BrCl(g) is 14.7 kJmol-1 . The standard enthalpies for the atomization of Br2(l) and Cl2(g)

natita [175]

Explanation:

Equation of the reaction:

Br2(l) + Cl2(g) --> 2BrCl(g)

The enthalpy change for this reaction will be equal to twice the standard enthalpy change of formation for bromine monochloride, BrCl.

The standard enthalpy change of formation for a compound,

ΔH°f, is the change in enthalpy when one mole of that compound is formed from its constituent elements in their standard state at a pressure of 1 atm.

This means that the standard enthalpy change of formation will correspond to the change in enthalpy associated with this reaction

1/2Br2(g) + 1/2Cl2(g) → BrCl(g)

Here, ΔH°rxn = ΔH°f

This means that the enthalpy change for this reaction will be twice the value of ΔH°f = 2 moles BrCl

Using Hess' law,

ΔH°f = total energy of reactant - total energy of product

= (1/2 * (+112) + 1/2 * (+121)) - 14.7

= 101.8 kJ/mol

ΔH°rxn = 101.8 kJ/mol.

8 0

3 years ago