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valentina_108 [34]
3 years ago
12

When a gas is compressed, the molecules are pushed closer together causing the gas to ______.

Physics
2 answers:
yan [13]3 years ago
6 0

Answer: Option (b) is the correct answer.

Explanation:

When gas is compressed then molecules of gas will come closer to each other. Though molecules already had kinetic energy and on compressing the molecules will collide more rapidly with each other.

As a result, energy will be released in the form of heat. Thus, there will be rise in temperature.

Hence, we can conclude that when a gas is compressed, the molecules are pushed closer together causing the gas to rise in temperature.

AfilCa [17]3 years ago
3 0
The answer is "rise in temperature". Think of when you're in a crowded place. When it's crowded it gets hot because of the energy radiating off of everyone around you.
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Scientists observe an approaching asteroid that is on a collision course with
nasty-shy [4]

Answer:

The approximate velocity the rocket must have to stop the asteroid completely after the collision is;

C. -324 m/s

Explanation:

The parameters of the asteroid and the rocket are;

The mass of the asteroid, m₁ = 11,000 kg

The initial velocity with which the asteroid is approaching Earth, v₁ = 50 m/s

The mass of the rocket, m₂ = 1700 kg

The initial velocity of the rocket = v₂

The final velocity of the combined asteroid and rocket after the collision, v₃ = 0 m/s

By the law of conservation of linear momentum, we have;

The total initial momentum = The total final momentum

m₁·v₁ + m₂·v₂ = (m₁ + m₂)·v₃

Substituting the known values, we get;

11,000 kg × 50 m/s + 1,700 kg × v₂ = (11,000 kg + 1,700 kg) × 0 m/s

11,000 kg × 50 m/s + 1,700 kg × v₂ = 0

∴ 1,700 kg × v₂ = -11,000 kg × 50 m/s

v₂ = (-11,000 kg × 50 m/s)/(1,700 kg) = -323.529412 m/s ≈ -324 m/s

The approximate initial velocity the jet must have to completely stop the asteroid after the collision is -324 m/s.

3 0
3 years ago
At an amusement park there are 200-kg bumper cars A, B, and C that have riders with masses of 55 kg, 90 kg, and 42.5 kg respecti
erma4kov [3.2K]

Answer:

Vb = 0.334 m/s

Va = -1.265 m/s

Vc = 1.424 m/s

Explanation:

Favorite Answer

Initial momentum = 255(2) – 242.5(1.5) = 146.25

Final momentum = 255Va + 290Vb + 242.5 Vc = 146.25

Vb - Va = 0.8(2) = 1.6

Vc - Vb = 0.8(1.5) = 1.2

Va = Vb -1.6

Vc = Vb + 1.2

255(Vb -1.6) + 290Vb + 242.5(Vb + 1.2) = 146.25

255 Vb – 408 + 290 Vb + 242.5 Vb + 291 = 146.25

787.5 Vb = 263.25

Vb = 0.334 m/s

Va = Vb -1.6 = 0.334 – 1.6 = -1.265 m/s

Vc = Vb + 1.2 = 0.224 + 1.2 = 1.424 m/s

8 0
3 years ago
ANSWER QUESTIONS WITH CORRECT ANSWERS FOR BRAINLIST! ANSWER ASAP!!
devlian [24]

Answer:

So, this is not the answer because I suck like that (hehe >:3) but here's some helps.

Explanation:

1. The magnitude of the net force acting on an object is equal to the mass of the object multiplied by the acceleration of the object as shown in the formula below.

2. If the net force acting on an object is zero, then the object is not accelerating, and is in a state known as equilibrium.

3. This will be were you use the info I gave to figure it out. I hope this wasn't completely unhelpful.

7 0
4 years ago
Which type of light-matter interaction causes glare?
AleksandrR [38]

Answer:

I think the reflection of light off of a shiny surface is the answer... Hope this helps

Explanation:

3 0
3 years ago
How quickly a leaf grows is proportional how big [ie the surface area] the leaf is. If the area of the leaf grows from 2cm2 to 3
marusya05 [52]

Answer: 9 days

Explanation:

  • Step 1

Let the rate of Leaf growth <em>r</em> be defined as, \frac{Increase  in  area}{time taken} = \frac{A1 - A}{t}

where <em>A</em> is initial area of the leaf, <em>A1</em> is the final area of the leaf and<em> t</em> is the time taken for the increase in Area.

  • Express the proportional relationship in equation.

Given that rate of leaf growth, r is proportional to the surface area of the leaf A. we have r ∝ A.

r = kA, where k is the rate constant.

therefore, k = \frac{r}{A}

when A = 2cm^{2}, A1 = 3

so k = \frac{\frac{3 - 2}{3}}{2}

= \frac{1}{3} ÷ 2

= 0.33 ÷ 2

k = 0.167

  • After calculating the rate constant k, we then find the time t when A1 is 5cm^{2}
  • we have r = k × A1 = \frac{A1 - A}{t}

so, 0.167 × 2 = \frac{5 - 2}{t}

0.33 = \frac{3}{t}.

t = 3/0.33

Therefore, t = 9 days.

3 0
4 years ago
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