Answer:
V₂ = -22 V
Explanation:
Electric potential and field are related
ΔV = - E d
where ΔV is the potential difference between the plates, E the electric field and d the separation between the plates
In this exercise we are given the parcionero d = 4 mm = 0.004 m, the potential of one of the plates V1 = -6V and the value of the electric field E = 4000 V / m
V₂- V₁ = - E d
V₂ = - Ed + V₁
V₂ = - 4000 0.004 + (- 6)
V₂ = -16 - 6
V₂ = -22 V
Answer:
Many familiar physical quantities can be specified completely by giving a single number and the appropriate unit. For example, “a class period lasts 50 min” or “the gas tank in my car holds 65 L” or “the distance between two posts is 100 m.” A physical quantity that can be specified completely in this manner is called a scalar quantity. Scalar is a synonym of “number.” Time, mass, distance, length, volume, temperature, and energy are examples of scalar quantities.
The bulbs will produce lesser light than their capacity, In short they will be dimmer because the the energy will get divided in the number of bulbs.
Answer:
The average angular acceleration is ![\alpha =125.487 rad /s^2](https://tex.z-dn.net/?f=%5Calpha%20%3D125.487%20rad%20%2Fs%5E2)
Explanation:
From the question we are told that
From the question we are told that
The length of the bat is
\
The initial linear velocity is ![u = 0 m/s](https://tex.z-dn.net/?f=u%20%3D%200%20m%2Fs)
The time is ![t = 0.15s](https://tex.z-dn.net/?f=t%20%3D%200.15s)
The velocity at t is ![v = 16 m/s](https://tex.z-dn.net/?f=v%20%3D%2016%20m%2Fs)
Generally average angular acceleration is mathematically represented as
![\alpha = \frac{w_f - w_o}{t}](https://tex.z-dn.net/?f=%5Calpha%20%20%3D%20%5Cfrac%7Bw_f%20-%20w_o%7D%7Bt%7D)
Where
is the finial angular velocity which is mathematically evaluated as
![w_f = \frac{v}{l}](https://tex.z-dn.net/?f=w_f%20%3D%20%5Cfrac%7Bv%7D%7Bl%7D)
![w_f = \frac{16}{0.85}](https://tex.z-dn.net/?f=w_f%20%3D%20%5Cfrac%7B16%7D%7B0.85%7D)
![= 18.823 rad/s](https://tex.z-dn.net/?f=%3D%2018.823%20rad%2Fs)
and
is the initial angular velocity which is zero since initial linear velocity is zero
So
![\alpha = \frac{18.823 - 0}{0.15}](https://tex.z-dn.net/?f=%5Calpha%20%20%3D%20%5Cfrac%7B18.823%20-%200%7D%7B0.15%7D)
![\alpha =125.487 rad /s^2](https://tex.z-dn.net/?f=%5Calpha%20%3D125.487%20rad%20%2Fs%5E2)
Answer:
3x10⁴v
Explanation:
Using
Wavelength= h/ √(2m.Ke)
880nm = 6.6E-34/√ 2.9.1E-31 x me
Ke= 6.6E-34/880nm x 18.2E -31.
5.6E-27/18.2E-31
= 3 x 10⁴ Volts