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andrezito [222]
3 years ago
15

Ionic compound formula of magnesium nitrate​

Chemistry
1 answer:
alekssr [168]3 years ago
5 0

Yo sup??

Magnesium nitrate has the formula

Mg(NO3)2

Hope this helps

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You should know the location of safety equipment
s2008m [1.1K]
I would say you should use or test it once a week to ensure it is working properly in an active laboratory since it is a workplace with significant chemical hazards so it would give peace of mind to know on a quite regular basis that it can be relied on in case of an emergency like an eye flush for example.
7 0
3 years ago
A gas has an initial volume of 455 mL at 105ºC and a final volume of 235 mL. What is its final temperature in Celsius degrees?
Oksana_A [137]
Hello!

To solve this problem we're going to use the Charles' Law. This Law describes the relationship between Volume and Temperature in an ideal gas. Applying this law we have the following equation:

\frac{V1}{T1} = \frac{V2}{T2} \\  \\ T2= \frac{V2*T1}{V1}=  \frac{235 mL * 105  ^{\circ}C }{455 mL}=54,23 ^{\circ}C

So, the final temperature is 54,23 °C

Have a nice day!
5 0
4 years ago
Read 2 more answers
How much faster does ethane (C2H6) gas travel compared to chlorine gas?
zimovet [89]

Answer:

\large \boxed{\text{54 $\, \%$ faster }}

Explanation:

v_{\text{rms}} \propto \sqrt{\dfrac{3RT}{M}

if temperature is constant.  

v_{\text{rms}} \propto \sqrt{\dfrac{1}{M}

if we are comparing two gases,

\dfrac{v_{2}}{v_{1}} = \sqrt{\dfrac{M_{1}}{M_{2}}}

Let chlorine be Gas 1 and ethane be Gas 2

Data:

M₁ =  70.91 g/mol

M₂ = 30.07 g/mol

Calculation

\begin{array}{rcl}\dfrac{v_{2}}{v_{1}} & = & \sqrt{\dfrac{M_{1}}{M_{2}}}\\\\& = & \sqrt{\dfrac{70.91}{30.07}}\\\\& = & \sqrt{2.358}\\\\& = & \mathbf{1.54}\\\end{array}\\\text{Ethane molecules travel at 1.54 times the speed of chlorine molecules}\\\text{or $\large \boxed{\textbf{54 $\%$ faster }}$ than chlorine molecules}

5 0
3 years ago
A lithium flame has a characteristic red color due to emissions of wavelength 671 nm. What is the mass equivalence of 1 mol of p
e-lub [12.9K]

Answer:

1.98x10⁻¹² kg

Explanation:

The <em>energy of a photon</em> is given by:

  • E= hc/λ

h is Planck's constant, 6.626x10⁻³⁴ J·s

c is the speed of light, 3x10⁸ m/s

and λ is the wavelenght, 671 nm (or 6.71x10⁻⁷m)

  • E = 6.626x10⁻³⁴ J·s * 3x10⁸ m/s ÷ 6.71x10⁻⁷m = 2.96x10⁻¹⁹ J

Now we multiply that value by <em>Avogadro's number</em>, to <u>calculate the energy of 1 mol of such protons</u>:

  • 1 mol =  6.023x10²³ photons
  • 2.96x10⁻¹⁹ J *  6.023x10²³ = 1.78x10⁵ J

Finally we <u>calculate the mass equivalence</u> using the equation:

  • E=m*c²
  • m=E/c²
  • m =  1.78x10⁵ J / (3x10⁸ m/s)² = 1.98x10⁻¹² kg

6 0
3 years ago
Which of the following are ways that technology may be used in an investigation of clouds over Kansas City?
alexandr402 [8]

The answer is C. All of these.

8 0
3 years ago
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