As keisha runs the generator, which best describes what should happen to the needle that measures electric current? it will move
1 answer:
The diagram shows a simple electric generator. The needle that measures electric current will move back and forth between a largely positive and a large negative value.
- What is an electric generator?
- An electric generator is physically equivalent to an electric motor. but it converts mechanical energy into electrical energy.
- The electrical field generated is dependent on the inclination of the wire with respect to magnetic field lines, and this inclination changes over time,
because of that she will experience a varying electrical field, and thus a varying electric current will be zero.
The maximum positive value will occur when the wire is perpendicular to the magnetic field lines after one-fourth of rotation, and then zero.
Hence option C is correct.
The diagram shows a simple electric generator. The needle that measures electric current will move back and forth between a largely positive and a large negative value.
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0.125 mm . is the thickness of the sample.
<h3>What do you mean by hall voltage ?</h3>The Hall effect is the creation of a voltage difference (the Hall voltage) across an electrical conductor, which is transverse to an applied magnetic field perpendicular to the current and an electric current in the conductor. Edwin Hall made the discovery in 1879.
We need to know the material's current, magnetic field, length, number of charge carriers, and area in order to calculate the Hall voltage. The Hall voltage is computed using the formula: v=IBlneA=(100A)(1.5T)(1.0102m)(5.91028/m3)(1.61019C)(2.0105m2)=7.9106V.
lof4
First we have to plot those point Then we can use some computer program to fit those point linearly to get slope
of that graph a and interception b. We already know, from theory, that Hall's voltage AVH and magnitude of
magnetic field B are connected as
Δ
where I is current trough probe, n is concentration of charge carriers, q = 1.6 • 10¯19 C is charge of charge
carries and t is thickness of the material. We have put the data from the problem on a graph and fitted linearly and
got
a = 100 μ
b = —0.02 μV.
As we can see, our result are in agreement with theoretical assumptions because interception b is almost O, and a
is asked relation between Hall's voltage A VH and magnitude of magnetic field B. Then we can write
ΔVH = V/TB
(4) Then we can use result (4) and numbers from the textbook to calculate the thickness of the sample as
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Answer:
It is real, inverted, and smaller than the object.
Explanation:
Let's start by using the lens equation to find the location of the image:
where we have:
q = ? is the distance of the image from the lens
f = 15 cm is the focal length (positive for a converging lens)
p = 50 cm is the distance of the object from the lens
Solving the equation for q, we find
The sign of q is positive, so the image is real.
Now let's also write the magnification equation:
where
are the size of the image and of the object
By substituting p = 50 cm and q = 21.3 cm, we find
So we notice that:
: this means that the image is smaller than the object
: this means that the image is inverted
so, the correct option is:
It is real, inverted, and smaller than the object.