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s2008m [1.1K]
3 years ago
9

Knowing that 0.80kg object weighs 8.0n find the acceleration of a 0.80kg stone in free fall

Physics
2 answers:
DENIUS [597]3 years ago
7 0
This question can be easily solved with newton's second law of motion.
F=ma
a=F/m
=8/0.8
=10m/s^2
vovikov84 [41]3 years ago
4 0

Answer : a = 10 m/s^{2}

Explanation :

Given that,

Mass = 0.80 kg

Force = 8.0 N

According to newton second law

F = ma

a = \dfrac{F}{m}

a = \dfrac{8.0 N}{0.80kg}

The acceleration is

a = 10 m/s^{2}

Hence, this is the required solution .


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You are viewing a read out of an oscilloscope that shows you when different voltages in a circuit maximize. If the period of the
Aleksandr-060686 [28]

Answer:

The time is  t = 0.02 \ s  

Explanation:

From the question we are told that

  The period of the circuit is  T  =  0.04

Generally voltage maximization of the capacitor occurs during the voltage minimization of the inductor and vise versa

So the time between the voltage maximization of the capacitor and that of the inductor is mathematically represented as

           t = \frac{T}{2}

=>        t = \frac{0.04}{2}

=>        t = 0.02 \ s  

7 0
2 years ago
A 66​-foot-tall woman walks at 55 ​ft/s toward a street light that is 2424 ft above the ground. What is the rate of change of th
I am Lyosha [343]

Answer:

a. \frac{dx}{dt}=20ft/s

b. \frac{d(x+L)}{dt}==25ft/s

Explanation:

Using the triangle theorem both triangle the woman makes between the light so the rate of change of length can use geometry first

tan(\beta)=\frac{24ft}{L+x}=\frac{6ft}{x}

Solve to find the rate relation

x=\frac{24}{6}*L

x=4*L

Now the rate of the change rate

\frac{dx}{dt}=4*\frac{dL}{dt}

\frac{dx}{dt}=4*5ft/s=20ft/s

Finally the rate of her shadow moving

\frac{d(x+L)}{dt}=\frac{dx}{dt}+\frac{dL}{dt}

\frac{d(x+L)}{dt}=20ft/s+5ft/s=25ft/s

5 0
2 years ago
A pogo stick has a spring with a force constant of 2.50 × 104 N/m , which can be compressed 11.2 cm. what maximum height, in met
AleksandrR [38]

Answer:

h = 36.4 cm

Explanation:

given,

spring constant = 2.5 x 10⁴ N/m

compressed distance = 11.2 cm = 0.112 m

mass of the child = 44 kg

maximum height = ?

by energy of conservation

K.E_i +P.E_i= K.E_f + P.E_f

\dfrac{1}{2}kx^2 = mgh

\dfrac{1}{2}\times 2.5 \times 10^4 \times 0.112^2 = 44\times 9.8 \times h

\dfrac{1}{2}\times 2.5 \times 10^4 \times 0.112^2 = 44\times 9.8 \times h

156.8 = 44 \times 9.8 \times h

h = \dfrac{156.8}{44 \times 9.8}

h = 0.364 m

h = 36.4 cm

7 0
2 years ago
Goldie Doldfish, a speed swimmer, loves to rece around the parks pond, which is 0.5 miles around. If she can swim around the tra
rosijanka [135]

Answer:

Her average speed is 0.25 miles / hour.

Explanation:

I did 0.5 divided by 2 = 0.25 miles / hour.

<em>Hope this helps! :)</em>


8 0
2 years ago
What happens to a wave when it moves from one medium to another?
Nina [5.8K]
One side of the wave changes speed before the other side, causing the wave to move
3 0
3 years ago
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