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3 years ago

Someone help me I will mark brainless it’s 2 questions .

Physics

1 answer:

AveGali [126]3 years ago

5 0

Answer:

1.C,2.A

Explanation:

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A simple pendulum consists of a mass M attached to a string oflength L andnegligible mass. For this system, when undergoing smal

PilotLPTM [1.2K]

The frequency of the pendulum is independent of the mass on the end. (c)

This means that it doesn't matter if you hang a piece of spaghetti or a school bus from the bottom end. If there is no air resistance, and no friction at the top end, and the string has no mass, then the time it takes the pendulum to swing from one side to the other <u><em>only</em></u> depends on the <u><em>length</em></u> of the string.

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3 years ago

what would happen to the size of the shadow if the distance between the light and the hand is increased.

Sergio039 [100]

I don’t think I will have any time to go

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3 years ago

What gravitational force does the earth exert on a person

lara [203]

The gravitational force exerted by the earth on a person standing on the earth's surface is 602.74 N.

<h3>What is the gravitational force of the earth on the person?</h3>

The gravitational force exerted by the earth on a person standing on the earth's surface is given below as follows:

$F = \frac{Gm^{1}m^{2}}{r^{2}}$

where

G = 6.67 * 10⁻¹¹

m¹ = 62 kg

m² = 5.97 * 10²⁷ kg

r = 6.4 * 10⁶ m

$F = \frac{5.97*10^{24}*62*6.67*10^{-11}}{(6.4*10^{6}){2}} = 602.74\:N$

Therefore, the gravitational force exerted by the earth on a person standing on the earth's surface is 602.74 N.

Learn more about gravitational force at: brainly.com/question/940770

#SPJ1

7 0

2 years ago

8. Differentiate between each of these land designations made during the Progressive Era:

aliya0001 [1]

Answer:djhssnjsksksmksjsbhddbd

Explanation:

Hsjdbdkxlziucychcjxnsbsb

7 0

3 years ago

Here we will calculate the work per unit charge on an electron moving between two potentials. A 9.0 V battery is connected acros

Svet_ta [14]

Answer:

2000 V/m

1778021.69323 m/s

Explanation:

V = Voltage = 9 V = $\Delta V$

q = Charge of proton = $1.6\times 10^{-19}\ C$

m = Mass of electron = $9.11\times 10^{-31}\ kg$

v = Velocity of electron

Electric field is given by

$E=\dfrac{V}{d}\\\Rightarrow E=\dfrac{9}{4.5\times 10^{-3}}\\\Rightarrow E=2000\ V/m$

The electric field is 2000 V/m

Here, the energy of the system is conserved

$\dfrac{1}{2}mv^2=q\Delta V\\\Rightarrow v=\sqrt{\dfrac{2q\Delta V}{m}}\\\Rightarrow v=\sqrt{\dfrac{2\times 1.6\times 10^{-19}\times 9}{9.11\times 10^{-31}}}\\\Rightarrow v=1778021.69323\ m/s$

The velocity of the electron is 1778021.69323 m/s

4 0

3 years ago